अवकल समीकरण \(\rm 2y\frac{dx}{dy}+ x = 5y^{2}\) 

  1. \(\rm \sqrt{y}\)
  2. y2
  3. y
  4. \(\rm \frac{1}{\sqrt{y}}\)

Answer (Detailed Solution Below)

Option 1 : \(\rm \sqrt{y}\)
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Detailed Solution

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संकल्पना: 

संकलन गुणक, (IF) अवकल समीकरणासाठी, \(\rm\frac{dx}{dy}+Px= Q\)जेथे P आणि Q ला y चे सतत कार्य दिले जाते.

IF = \(\rm e^{\int Pdy}\) 

Calculation:

दिलेले समीकरण असे सरळ केले जाऊ शकते, 

\(\rm \frac{\mathrm{d} x}{\mathrm{d} y}+ \frac{x}{2y} = \frac{5}{2}y\)   

मानक समीकरणाची समीकरणएक ची तुलना केल्यावर , \(\rm\frac{dx}{dy}+Px= Q\) , मिळते ,

P = \(\rm \frac{1}{2y}\) आणि Q = \(\rm \frac{5}{2}y\)

 ∴ IF = \(\rm e^{\int Pdy}\) = \(\rm e^{\int \frac{1}{2y}dy}\) 

⇒ IF = \(\rm e^{\frac{1}{2}\log y}\) = \(\rm e^{\log y^{\frac{1}{2}}}\)  

IF = \(\rm \sqrt{y}\) .  ( ∵ \(\rm e^{a \log x}= x^{a}\) ) 

पर्याय 1 हे योग्य उत्तर आहे. 

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