Question
Download Solution PDF9592450, 9592330, 9592885, 9592741 എന്നീ സംഖ്യകളിൽ ഏതിനെയാണ് 11 കൊണ്ട് ഹരിക്കാൻ കഴിയുക?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFഉപയോഗിച്ച ആശയം:
അക്കങ്ങളുടെ ആകെത്തുക തമ്മിലുള്ള വ്യത്യാസം 11 ന്റെ ഗുണിതമാണെങ്കിൽ അല്ലെങ്കിൽ ഫലം 0 ആണെങ്കിൽ, ആ സംഖ്യയെ 11 കൊണ്ട് ഹരിക്കാനാകും.
ഉദാഹരണത്തിന്: 9383 = 9 + 8 - (3 + 3) = 17 - 6 = 11. അപ്പോൾ, 9383 നെ 11 കൊണ്ട് ഹരിക്കാനാകും.
കണക്കുകൂട്ടല് :
⇒ 9592885 = 9 + 9 + 8 + 5 - (5 + 2 + 8) = 18 + 13 - 15 = 31 - 15 = 16
⇒ 9592741 = 9 + 9 + 7 + 1 - (5 + 2 + 4) = 18 + 8 - 11 = 15
⇒ 9592450 = 9 + 9 + 4 + 0 - (5 + 2 + 5) = 18 + 4 - 12 = 10
⇒ 9592330 = 9 + 9 + 3 + 0 - (5 + 2 + 3) = 21 - 10 = 11
∴ ശരിയായ ഉത്തരം 9592330 ആണ്.
Last updated on Jun 13, 2025
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