Find the smallest 4 digit number which is divided by 8,10,12,15,20 and leaves the remainder as 7. 

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UP Police SI (दरोगा) Official PYP (Held On: 12 Nov 2021 Shift 2)
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  1. 1100
  2. 1073
  3. 1087
  4. 1080

Answer (Detailed Solution Below)

Option 3 : 1087
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यूपी पुलिस SI (दरोगा) सामान्य हिंदी मॉक टेस्ट
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Detailed Solution

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Given:

Find the smallest 4 digit number which is divided by 8, 10, 12, 15, 20 and leaves the remainder as 7.

Formula used:

LCM of the given numbers + remainder

Calculation:

LCM of 8, 10, 12, 15, 20 = 120

Smallest 4-digit number is 1000

1000 divided by 120 gives quotient 8 and remainder 40

⇒ 1000 + (120 - 40) = 1000 + 80 = 1080

⇒ 1080 + 7 = 1087

∴ The correct answer is option (3).

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