Question
Download Solution PDFPQRS एक समांतर चतुर्भुज है जिसमें PQ, 11 सेमी, QR, 13 सेमी और PR, 16 सेमी है। विकर्णों की लंबाई का अंतर क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
आसन्न भुजाएं = 11 सेमी, 13 सेमी
विकर्ण = 16 सेमी
अवधारणा:
एक समांतर चतुर्भुज के विकर्णों के वर्गों का योग, भुजाओं के वर्ग के योग के दोगुने के बराबर होता है।
गणना:
(d12 + d22) = 2(a2 + b2)
⇒ (162 + d22) = 2 (112 + 132)
⇒ d2 = √(242 + 338 - 256)
⇒ d2 = √ 324 = 18 सेमी
अभीष्ट अंतर = 18 - 16 = 2 सेमी
∴ अंतर 2 सेमी है।
Last updated on Jun 3, 2025
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