Question
Download Solution PDFएक आयत का परिमाप 40 सेमी है, और उसकी लंबाई (l) और चौड़ाई (b) के बीच का अंतर 6 सेमी है। आयत का क्षेत्रफल क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
परिमाप (P) = 40 सेमी
लंबाई और चौड़ाई के बीच अंतर = l - b = 6 सेमी
आयत के लिए परिमाप सूत्र:
P = 2(l + b)
दिए गए परिमाप को प्रतिस्थापित कीजिए:
2l + b = 40
l + b = 20.......................(समीकरण 1)
दिया गया अंतर:
l - b = 6............................(समीकरण 2)
समीकरण 1 और समीकरण 2 को जोड़ें:
(l + b) + (l - b) = 20 + 6
2l = 26
l = 13 सेमी
समीकरण 1 में l = 13 प्रतिस्थापित करें:
13 + b = 20
b = 7 सेमी
A = l × b = 13 × 7 = 91 सेमी2
इस प्रकार, सही उत्तर 91 सेमी² है।
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