यदि \(\rm y=x^{\sec^2x}\times\frac{1}{x^{\tan^2x}}\) है, तो \(\rm \frac{dy}{dx}=?\)

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  2. 0
  3. \(\rm 2x^{\sec^2x}\log\tan^2x\)
  4. 1

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दिया गया है:
\(\rm y=x^{\sec^2x}\times\frac{1}{x^{\tan^2x}}\)

अवधारणा:

त्रिकोणमितीय सर्वसमिका \(\rm \sec^2x-\tan^2x=1\) का उपयोग कीजिए। 

और अवकलज नियम \(\rm \frac{d}{dx}x^n=n x^{n-1}\) उपयोग कीजिए। 

गणना:

\(\rm y=x^{\sec^2x}\times\frac{1}{x^{\tan^2x}}\)

\(\rm \implies y=x^{\sec^2x}\times x^{-\tan^2x}\)

\(\rm \implies y=x^{\sec^2x-\tan^2x}\)

\(\rm \implies y=x\)

अब \(\rm x\) के सापेक्ष अवकलज करने पर,

हम प्राप्त करते हैं,

\(\rm \frac{dy}{dx}=1\)

अतः विकल्प (4) सही है।

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