C = 101.5 nF के लिए, श्रेणीक्रम अनुनाद परिपथ के लिए L निर्धारित करें यदि अनुनाद आवृत्ति 2800 Hz है।

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  1. 31.83 mH
  2. 16.32 mH
  3. 46.45 mH
  4. 26.56 mH

Answer (Detailed Solution Below)

Option 1 : 31.83 mH
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संकल्पना:

  • अनुनाद पर एक श्रेणीक्रम RLC परिपथ के लिए, प्रेरणिक प्रतिघात धारिता प्रतिघात के बराबर हो जाती है।
  • इस प्रकार, अनुनाद के समय, परिपथ पूर्ण प्रतिरोधी परिपथ के रूप में व्यवहार करता है।
  • अनुनादी आवृत्ति का मान निम्नलिखित द्वारा दी जाती है:\(ω_c=\frac{1}{\sqrt{LC}}~rad/sec\)

गणना:

दिए गए प्रश्न के लिए; R = 50 Ω, L = 0.4 H, C = 10 μF

\(f_c=\frac{1}{2\pi\sqrt{LC}}~Hz\)

\(2800= \;\frac{1}{2\pi{\sqrt {L\times {{101.5}^{ - 9}}}}}\)

L =31.83 mH

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