Question
Download Solution PDFFor C = 101.5 nF, determine L for the series resonant circuit if the resonant frequency is 2800 Hz.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
- For a series RLC circuit at resonance, the inductive reactance becomes equal to the capacitive reactance.
- Thus, at the time of resonance, the circuit behaves as a purely resistive circuit.
- The value of resonant frequency is given by:
\(ω_c=\frac{1}{\sqrt{LC}}~rad/sec\)
Calculation:
For the given question; R = 50 Ω, L = 0.4 H, C = 101.5 nF
\(f_c=\frac{1}{2\pi\sqrt{LC}}~Hz\)
\(2800= \;\frac{1}{2\pi{\sqrt {L\times {{101.5}\times10^{ - 9}}}}}\)
L =31.83 mH
Last updated on May 29, 2025
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