For which discovery did Henri Becquerel receive the Nobel Prize in Physics in 1903? 

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SSC CHSL Exam 2024 Tier-I Official Paper (Held On: 03 Jul, 2024 Shift 3)
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  1. Spontaneous Radioactivity
  2. Radium Emanation
  3. Diagnostic Radiography 
  4. Radioactive Elements

Answer (Detailed Solution Below)

Option 1 : Spontaneous Radioactivity
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SSC CHSL Exam 2023 Tier-I Official Paper (Held On: 02 Aug 2023 Shift 1)
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Detailed Solution

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The correct answer is Spontaneous Radioactivity

Key Points

  • Henri Becquerel received the Nobel Prize in Physics in 1903 for his discovery of Spontaneous Radioactivity.
  • He shared the prize with Marie Curie and Pierre Curie, who were also recognized for their work in the field of radioactivity.
  • Henri Becquerel's discovery was pivotal in the development of atomic physics and the understanding of radioactive phenomena.
  • This discovery was made when Becquerel found that uranium salts emitted rays that could expose photographic plates, even without sunlight.

Additional Information

  • The Nobel Prize in Physics was established by the will of Alfred Nobel, the inventor of dynamite, and has been awarded annually since 1901.
  • Henri Becquerel's work laid the groundwork for future research and applications in nuclear energy and medical diagnostics.
  • Radioactivity is the process by which unstable atomic nuclei lose energy by emitting radiation, which can include alpha particles, beta particles, and gamma rays.
  • Becquerel's discovery was initially accidental but led to significant advancements in both theoretical and applied physics.
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