Question
Download Solution PDFApproximately, the given data where Pearson's second measure of skewness = 0.33, arithmetic mean = 116 and median = 105, then find standard deviation and coefficient of variation
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFormula Used:
Skewness (Skp) = \(\frac{3(Mean~-~Median)}{Standard~deviation}\)
Coefficient of variation = \(\frac{Standard~deviation}{Mean}\) × 100
Given:
Pearsaons measure of skewness = 0.33
Mean (x̅) = 116
Median (Md) = 105
Calculation:
We know that,
Skewness (Skp) = \(\frac{3(Mean~-~Median)}{Standard~deviation}\)
⇒ 0.33 = 3(x̅ - Md)/σ
⇒ 0.33 = 3(116 – 105)/σ
⇒ σ = 33/0.33
⇒ σ = 100
Then the standard deviation is 100.
Coefficient of variation (CV) = \(\frac{Standard~deviation}{Mean}\)
⇒ (σ/x̅) × 100
⇒ CV = (100/116) × 100
⇒ (0.8621) × 100
∴ Coefficient of variation is 86.21
Last updated on May 30, 2025
->UPSC has released UPSC NDA 2 Notification on 28th May 2025 announcing the NDA 2 vacancies.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced for cycle 2. The written examination will be held on 14th September 2025.
-> Earlier, the UPSC NDA 1 Exam Result has been released on the official website.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.