Question
Download Solution PDFलगभग, दिए गए आकड़ो में जहां पियरसन की विषमता की दूसरा माप = 0.33, अंकगणितीय माध्य = 116 और माध्यिका = 105 है, तो मानक विचलन और परिवर्तिता का गुणांक ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFप्रयुक्त सूत्र :
विषमता (Skp) = \(\frac{3(Mean~-~Median)}{Standard~deviation}\)
परिवर्तिता का गुणांक = \(\frac{Standard~deviation}{Mean}\) × 100
दिया गया है:
पियरसन की विषमता की माप = 0.33
माध्य (x̅) = 116
माध्यिका (Md) = 105
गणना:
हम जानते हैं कि,
विषमता (Skp) = \(\frac{3(Mean~-~Median)}{Standard~deviation}\)
⇒ 0.33 = 3(x̅ - Md)/σ
⇒ 0.33 = 3(116 – 105)/σ
⇒ σ = 33/0.33
⇒ σ = 100
तो मानक विचलन 100 है।
परिवर्तिता का गुणांक (CV) = \(\frac{Standard~deviation}{Mean}\)
⇒ (σ/x̅) × 100
⇒ CV = (100/116) × 100
⇒ (0.8621) × 100
∴ परिवर्तिता का गुणांक 86.21 है।
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