For the study purpose, the mean of the observations is 148 gm and standard deviation is 17.4 gm. Approximately, the coefficient of variation equals to:

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SSC CGL JSO Tier-II, 2018 (Statistics) Official Paper-III (Held On: 14 Sept, 2019)
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  1. 0.11
  2. 0.14
  3. 0.12
  4. 0.13

Answer (Detailed Solution Below)

Option 3 : 0.12
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Detailed Solution

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Concept:

Coefficient of variation = \(\rm \frac{\sigma _{x}}{\bar{x}}\)

Where, 

\(\rm \sigma _{x}\) = Standard Deviation

\(\rm \bar{x}\) = Mean of the observations

Calculation:

Coefficient of variation = \(\rm \frac{17.4}{148}\)

∴ Coefficient of variation is  0.12

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