Question
Download Solution PDFA cyclic heat engine operates between a source temperature of 727°C and a sink temperature of 27°C. Maximum efficiency of the engine is _________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For the maximum efficiency of the heat engine, the heat engine cycle should reject the least rate of heat (QL) which is only possible when it operates on the Carnot cycle.
For maximum efficiency of heat engines,
\(η = \frac{W}{{{Q_H}}} = \frac{{{T_H} - {T_L}}}{{{T_H}}} = 1 - \frac{{{T_L}}}{{{T_H}}}\)
Calculation:
Given TH = 727°C = 1000 K, TL = 27°C = 300 K
\(η = 1 - \frac{{{T_L}}}{{{T_H}}} = 1 - \frac{{300}}{{1000}}\)
η = 0.70 = 70%
Last updated on May 28, 2025
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