Decimals MCQ Quiz - Objective Question with Answer for Decimals - Download Free PDF

Given:

The value of 

Formula Used:

Calculation:

Here, a = 0.96 and b = 0.1 .

Using the formula:

⇒

⇒ 0.96 - 0.1

⇒ 0.86

The correct answer is option 3.

Given:

Number 1 = 0.18

Number 2 = 0.004

Formula used:

How many times greater = Number 1/Number 2

Calculation:

⇒

⇒

∴ The correct answer is option (4).

Given:

The value of 

Formula Used:

Calculation:

Here, a = 0.96 and b = 0.1 .

Using the formula:

⇒

⇒ 0.96 - 0.1

⇒ 0.86

The correct answer is option 3.

Given:

6.3 × 6.3 + 2 × 6.3 × 3.7 + 3.7 × 3.7

Formula used:

(a + b)² = a² + 2ab + b²

Calculation:

6.3 × 6.3 + 2 × 6.3 × 3.7 + 3.7 × 3.7

⇒ (6.3 + 3.7)²

⇒ 10²

⇒ 100

∴ The correct answer is option (2).

Given:

(0.008 ÷ 0.04) + (0.006 ÷ ?) + (0.004 ÷ 0.02) = 0.6

Calculations:

(0.008 ÷ 0.04) + (0.006 ÷ ?) + (0.004 ÷ 0.02) = 0.6

0.2 + (0.006 ÷ ?) + 0.2 = 0.6

0.4 + (0.006 ÷ ?) = 0.6

⇒ (0.006 ÷ ?) = 0.6 - 0.4 = 0.2

Now, solve for ?:

0.006 ÷ ? = 0.2

⇒ ? = 0.006 ÷ 0.2 = 0.03

∴ The value that should come in place of question mark is 0.03.

Since,

a2 - b2 = (a - b) ( a + b)

⇒ 0.9 × 0.7 = 0.63

∴ Answer is 0.63

Given expression,

(81.84 + 118.16) ÷ 5³ = 1.2 × 2 + ?

⇒ 200 ÷ 5³ = 1.2 × 2 + ?

⇒ 200 ÷ 125 = 1.2 × 2 +?

⇒ 1.6 = 2.4 + ?

⇒ ? = -0.8

Concept used:

Given expression is,

⇒ (?)³ × 10 = 13230 ÷ (9.261 ÷ 7)

⇒ (?)³ × 10 = 13230 ÷ (1.323)

⇒ (?)³ × 10 = 10000

⇒ (?)³ = 1000

⇒ (?)³ = (10)³

⇒ ? = 10

Mistake Points

In this type of question, in the numerator, there are 6.75 and 4.25, while in the denominator there is 67.5, and 42.5 is present in multiplication.

From the denominator, we can write 67.5 × 67.5 as 6.75 × 10 × 6.75 × 10 = 100 × (6.75), and similarly for other terms.

Therefore we take 100 as common from the denominator.

Identity used:

a³ - b³ = (a - b) (a² + b² + ab)

Calculation:

⇒ ? = 2.5/100

⇒ ? = 0.025

∴ ? = 0.025

1132.757 – 2315.996 – 1753.829 + 2 × 2846.639

= 1133 – 2316 – 1754 + 5694

= (1133 + 5694) – (2316 + 1754 )

= 6827 – 4070

= 2757

Calculation:

Let x = 0.0181818....

⇒ 10x = 0.1818....      ----eq (1)

⇒ 1000x = 18.1818....      ----eq (2)

Now, eq (2) - eq (1)

⇒ 1000x - 10x = 18.1818... - 0.1818...

⇒ 990x = 18

⇒ x = 18/990

⇒ x = 1/55

∴ The fraction of  is 1/55

Shortcut Trick

">ab¯" role="presentation" style="display: inline; position: relative;" tabindex="0">

⇒ ">ab¯" role="presentation" style="display: inline; position: relative;" tabindex="0">

⇒ 2/110 = 1/55

∴ The fraction of  is 1/55.
">ab¯" role="presentation" style="display: inline; position: relative;" tabindex="0">ab" id="MathJax-Element-5-Frame" role="presentation" style="position: relative;" tabindex="0">abab = ab/99

Calculations:

0.36 of 52.5 + ? of 35 = 57.4

⇒ 18.9 + ? of 35 = 57.4

⇒ ? of 35 = (57.4 − 18.9)

⇒ ? = 38.5/35 

⇒ ? = 1.1

Given:

 {(.98)3 + (0.02)3 + 3 × 0.98 × 0.02 – 1}

Concept used:

(a + b)3 = a3 + b3 + 3ab(a + b)

Calculation:

⇒ [(.98)³ + (0.02)³ + 3 × 0.98 × 0.02(0.98 + 0.02)} – 1]

Now, first term is of the form (a + b)3 where a = .98 and b = 0.02

⇒ (0.98 + 0.02)³ – 1 = 1 – 1 = 0

∴ The value is 0.

Given:

The given expression = (1.6)3 - (0.9)3 - (0.7)3

Formula used:

If a + b + c = 0, then a³ + b³ + c³ = 3abc

Calculation:

(1.6)3 - (0.9)3 - (0.7)3

= (1.6)3 + (- 0.9)3 + (- 0.7)3

= 3 × 1.6 × (- 0.9) × (- 0.7)  [∵ 1.6 - 0.9 - 0.7 = 0]

= 3.024

∴ The value of the given expression is 3.024

Concept used:

BODMAS 

Calculation:

= (9.6 × 3.6 ÷ 7.2 + 10.8 of  - )

= (9.6 × 3.6 ÷ 7.2 + 0.6  - )

= (9.6 ×  + 0.6  - )

= (4.8 + 0.6  - )

= 

= 

= 5.3

Answer is 5.3