Bodmas Rule MCQ Quiz - Objective Question with Answer for Bodmas Rule - Download Free PDF
Last updated on Jun 17, 2025
Latest Bodmas Rule MCQ Objective Questions
Bodmas Rule Question 1:
Which one is the largest among the fractions \(\left(\frac{4}{9}\right),\left(\frac{5}{8}\right),\left(\frac{2}{3}\right)\) and \(\left(\frac{3}{4}\right) \)?
Answer (Detailed Solution Below)
Bodmas Rule Question 1 Detailed Solution
Given:
The fractions are: (4/9), (5/8), (2/3), and (3/4).
Method:
We will compare the fractions by converting them to decimals or finding a common denominator. First, let's convert each fraction to a decimal:
4/9 = 0.4444
5/8 = 0.625
2/3 = 0.6666
3/4 = 0.75
Comparing the decimals:
0.4444, 0.625, 0.6666, and 0.75
Conclusion:
The largest value is 0.75, which corresponds to the fraction 3/4.
Therefore, the largest fraction is 3/4.
Bodmas Rule Question 2:
Find the value of \(\rm \left[(20\times 13)\times \left\{4\div 4\times \frac{(19-13)}{3}\right\}\right]\)
Answer (Detailed Solution Below)
Bodmas Rule Question 2 Detailed Solution
Given:
The expression is: (20 × 13) × {4 ÷ 4 × (19 - 13) / 3}
Formula Used:
Follow the BODMAS rule (Brackets, Orders, Division, Multiplication, Addition, Subtraction).
Calculation:
⇒ (20 × 13) × {4 ÷ 4 × (19 - 13) / 3}
⇒ (20 × 13) × {4 ÷ 4 × 6 / 3}
⇒ (20 × 13) × {1 × 6 / 3}
⇒ (20 × 13) × 2
⇒ 20 × 13 = 260
⇒ 260 × 2 = 520
The value of the expression is 520.
Bodmas Rule Question 3:
Find the value of \(\left[(91 \div 7) \times\left\{\frac{64}{4}+\frac{17}{6} \times(8-2)\right\}\right]\)
Answer (Detailed Solution Below)
Bodmas Rule Question 3 Detailed Solution
Given:
Expression: [(91 ÷ 7) × {(64 ÷ 4) + (17 ÷ 6) × (8 - 2)}]
Formula Used:
Order of operations (BODMAS): Solve inside brackets first, then division/multiplication, and finally addition/subtraction.
Calculation:
⇒ [(91 ÷ 7) × {(64 ÷ 4) + (17 ÷ 6) × (8 - 2)}]
⇒ (13) × {(16) + (17 ÷ 6) × (6)}
⇒ (13) × {16 + (17 × 6 ÷ 6)}
⇒ (13) × {16 + 17}
⇒ 13 × 33
⇒ 429
∴ The value of [(91 ÷ 7) × {(64 ÷ 4) + (17 ÷ 6) × (8 - 2)}] is 429.
Bodmas Rule Question 4:
The value of 44 × (84 ÷ 7) ÷ 2 - {3 × 10 + 10 - (6 - 3) ÷ 3} is:
Answer (Detailed Solution Below)
Bodmas Rule Question 4 Detailed Solution
Given:
The expression to solve is: 44 × (84 ÷ 7) ÷ 2 - {3 × 10 + 10 - (6 - 3) ÷ 3}
Calculation:
44 × (84 ÷ 7) ÷ 2 - {3 × 10 + 10 - (6 - 3) ÷ 3}
44 × 12 ÷ 2 - {3 × 10 + 10 - 3 ÷ 3}
44 × 6 - {30 + 10 - 1}
264 - 39 = 225
The final value of the expression is 225.
Bodmas Rule Question 5:
What value should come in the place of question mark (?) in the following question:
10620 ÷ [(3/4) (72 + 66) - 20(3/4)] = ?
Answer (Detailed Solution Below)
Bodmas Rule Question 5 Detailed Solution
Given:
10620 ÷ [(3/4) (72 + 66) - 20(3/4)] = ?
Formula Used:
Division of fractions: a ÷ (b/c) = a × (c/b)
Order of operations (BODMAS): Brackets → Orders (powers, roots) → Division → Multiplication → Addition → Subtraction
Calculation:
10620 ÷ [(3/4) (72 + 66) - 20(3/4)] = ?
⇒ 10620 ÷ [(3/4) (138) - 60/4)] = ?
⇒ 10620 ÷ [414/4 - 60/4] = ?
⇒ 10620 ÷ 354/4 = ?
⇒ 10620 × 4/354 = ?
⇒ 120
∴ Option 3 is the correct answer.
Top Bodmas Rule MCQ Objective Questions
What will come in the place of question mark (?) in the following question?
\(? = \sqrt[5]{{{{\left( {243} \right)}^2}}}\)
Answer (Detailed Solution Below)
Bodmas Rule Question 6 Detailed Solution
Download Solution PDFSolution:
We have to follow the BODMAS rule
Calculation:
\(? = \sqrt[5]{{{{\left( {243} \right)}^2}}}\)
\(⇒ ? = (243)^{\frac{2}{5}}\)
\(⇒ ? = (3 × 3 × 3 × 3 × 3)^{2⁄5}\)
\(⇒ ? = (3^5)^{2⁄5}\)
⇒ ? = 32
∴ ? = 9Find the value of:
\(\frac{{\left( {0.0112 - 0.0012} \right)\;of\;0.14\; + \;0.25\; \times \;0.2}}{{0.02\; \times \;0.01}}\)
Answer (Detailed Solution Below)
Bodmas Rule Question 7 Detailed Solution
Download Solution PDFWhat will come in place of the question mark ‘?’ in the following question?
(4 × 4)3 ÷ (512 ÷ 8)4 × (32 × 8)4 = (2 × 2)(? + 4)Answer (Detailed Solution Below)
Bodmas Rule Question 8 Detailed Solution
Download Solution PDFConcept used:
ax × ay = ax + y
ax ÷ ay = ax - y
Calculation:
(4 × 4)3 ÷ (512 ÷ 8)4 × (32 × 8)4 = (2 × 2)(? + 4)
⇒ 46 ÷ (64)4 × 2564 = (4)(? + 4)
⇒ 46 ÷ (43)4 × (44)4 = (4)(? + 4)
⇒ 4(6 + 16 - 12) = (4)(? + 4)
⇒ 410 = (4)(? + 4)
So, ? + 4 = 10
⇒ ? = 10 - 4
∴ ? = 6What should come at the place of ‘?’ in the following question?
1251/3 × 271/3 × 1254/3 = 15 × 5?Answer (Detailed Solution Below)
Bodmas Rule Question 9 Detailed Solution
Download Solution PDFFollow BODMAS (Brackets, Of, Division, Multiplication, Addition, Subtraction) rule to solve this question, as per the order given below,
Step-1- Parts of an equation enclosed in 'Brackets' must be solved inside the bracket first,
Step-2- Then any mathematical 'Of' or 'Exponent' must be solved,
Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,
Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.
1251/3 × 271/3 × 1254/3 = 15 × 5?
⇒ 5 × 3 × 54 = 15× 5x
⇒ 15 × 5 4 = 15× 5x
⇒ x = 4
Hence option 4 is correct.
Simplify (957 + 932)2 - 4 × 957 × 932.
Answer (Detailed Solution Below)
Bodmas Rule Question 10 Detailed Solution
Download Solution PDFShortcut Trick Formula:
(a+b)2 - 4ab = (a-b)2
Calculation:
(957 + 932)2 - 4 × 957 × 932
= (957 - 932)2
= 252 = 625
Alternate Method GIVEN:
\(( 957 + 932 )^2\) - 4 × 957 × 932.
FORMULA USED:
BODMAS
CALCULATION :
⇒ \((1889)^2\) - 4 × 957 × 932
⇒ 3568321 - 4 × 957 × 932
⇒ 3568321 - 3567696 = 625
∴ The value is 625.
What should come in the place of question mark (?) in the following question?
\(\frac{{7.2}}{{\sqrt[3]{{0.729}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
Answer (Detailed Solution Below)
Bodmas Rule Question 11 Detailed Solution
Download Solution PDFConcept used:
Follow BODMAS rule to solve this question, as per the order given below:
\(\frac{{7.2}}{{\sqrt[3]{{0.729}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
\(\Rightarrow \frac{{7.2}}{{\sqrt[3]{{\frac{{729}}{{1000}}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
\(\Rightarrow \frac{{7.2}}{{\sqrt[3]{{{{\left( {\frac{9}{{10}}} \right)}^3}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
\(\Rightarrow {\rm{\;}}\frac{{7.2}}{{\sqrt[3]{{{{\left( {0.9} \right)}^3}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
\(\Rightarrow \frac{{7.2}}{{0.9}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
⇒ 8 = (?)3/(2)3
⇒ (2)3 = (?)3/(2)3
⇒ 23 × 23 = (?)3
⇒ 43 = (?)3
⇒ ? = 4
∴ The value of ? is 4.63 - (- 3)(- 2 - 8 - 4) ÷ [3 {5 + (- 2)(- 1)}] = ?
Answer (Detailed Solution Below)
Bodmas Rule Question 12 Detailed Solution
Download Solution PDFUsing BODMAS rule:
⇒ 63 - (- 3)(- 2 - 8 - 4) ÷ [3 {5 + (- 2)(- 1)}]
⇒ 63 - (- 3)(- 2 - 8 - 4) ÷ [3 {5 + 2}]
⇒ 63 - (42) ÷ 21
⇒ 611962 × 56 ÷ 145 × 1021 = ?
Answer (Detailed Solution Below)
Bodmas Rule Question 13 Detailed Solution
Download Solution PDFConcept used:
Calculation:
1962 × 56 ÷ 145 × 1021
⇒ (142)2 × (56/145) × 1021
⇒ [144 × (56/145)] × 1021
⇒ (56/14) × 1021
⇒ 4 × 1021 = 4084
∴ The answer will be 4084.
\(56 \div \left[\frac{1}{3}\left\{ {15 + 12 - \left( {9 + 6 - \overline {5 + 7} } \right)} \right\} \right]= ? \)
Answer (Detailed Solution Below)
Bodmas Rule Question 14 Detailed Solution
Download Solution PDFConcept used:
Calculation:
\(56 \div \left[\frac{1}{3}\left\{ {15 + 12 - \left( {9 + 6 - \overline {5 + 7} } \right)} \right\} \right] \)
⇒ 56 ÷ [(1/3){15 + 12 - (9 + 6 - 12)}]
⇒ 56 ÷ [(1/3){15 + 12 - (15 - 12)}]
⇒ 56 ÷ [(1/3){15 + 12 - 3}]
⇒ 56 ÷ [(1/3){27 - 3}]
⇒ 56 ÷ [(1/3)(24)]
⇒ 56 ÷ 8
⇒ 7
∴ ? = 7
Important Points
If in any simplification problem there is ( ̅ ) bar sign above any operation then we should perform the operation at the beginning, whatever the operation is. Then we will follow the chart given above.
What approximate value should come in place of question mark ‘?’ in the following question?
1132.757 – 2315.996 – 1753.829 + 2 × 2846.639 = ?
Answer (Detailed Solution Below)
Bodmas Rule Question 15 Detailed Solution
Download Solution PDF1132.757 – 2315.996 – 1753.829 + 2 × 2846.639
= 1133 – 2316 – 1754 + 5694
= (1133 + 5694) – (2316 + 1754 )
= 6827 – 4070
= 2757