Bar Graph MCQ Quiz - Objective Question with Answer for Bar Graph - Download Free PDF
Last updated on Jun 6, 2025
Latest Bar Graph MCQ Objective Questions
Bar Graph Question 1:
Comprehension:
Direction: Study the following data carefully and answer the following questions.
The bar graph represents the percentage of people present in the bus just after every station.
After station 1, if 20% of previously present people getting into the Bus 1 at every Station (if there is space) then what percent seats remain empty after Station 2?
Answer (Detailed Solution Below)
Bar Graph Question 1 Detailed Solution
Given:
After Station 1 people present in Bus 1 = 75%
Calculation:
Let the capacity of Bus 1 be 100.
After Station 1, people presented in Bus 1 = 75
In next Station, people presented in Bus 2 = 75 + 75 × 20%
⇒ 90
Empty seats = 100 - 90 = 10
Required percentage = (10/100) × 100%
∴ 10% seats remain empty after station 2.
Bar Graph Question 2:
Comprehension:
Direction: Study the following data carefully and answer the following questions.
The bar graph represents the percentage of people present in the bus just after every station.
If capacity of both the buses are equal then what is the percentage of people present in both buses just after Station 3 ?
Answer (Detailed Solution Below)
Bar Graph Question 2 Detailed Solution
Given:
Just after Station 3 people present in Bus 1 = 50%
Just after Station 3 people present in Bus 2 = 40%
Capacity of both the buses are equal.
Calculation:
Let the total number of people in Bus 1 and Bus 2 be 100 and 100 respectively.
People presented in Bus 1 = 100 × 50% = 50
People presented in Bus 2 = 100 × 40% = 40
In Bus 1, Present people : Total people = 50 : 100
In Bus 2, Present people : Total people = 40 : 100
Percentage total people = {(50 + 40)/200} × 100
⇒ (90/200) × 100
⇒ 45%
∴ The total people present in both the buses is 45% just after Station 3.
Bar Graph Question 3:
Comprehension:
Direction: Study the following data carefully and answer the following questions.
The bar graph represents the percentage of people present in the bus just after every station.
What is the ratio of number of people present in Bus 2 just after Station 2 and in Bus 1 just after Station 4?
Answer (Detailed Solution Below)
Bar Graph Question 3 Detailed Solution
Calculation:
Here relation between capacity of Bus 1 and Bus 2 is not given, so the ratio cannot be found.
∴ The answer is data inadequate.
Bar Graph Question 4:
Comprehension:
Direction: Study the following data carefully and answer the following questions.
The bar graph represents the percentage of people present in the bus just after every station.
What is the difference between the people present in Bus 1 and Bus 2 just after Station 2 if the capacity of Bus 1 is 200 and Bus 2 is 300 ?
Answer (Detailed Solution Below)
Bar Graph Question 4 Detailed Solution
Given:
Capacity of Bus 1 = 200
People present in Bus 1 just after Station 2 = 40%
Capacity of Bus 2 = 300
People present in Bus 2 just after Station 2 = 20%
Calculation:
Number of people in Bus 1 just after Station 2 = 40% of 200
⇒ (2/5) × 200
⇒ 2 × 40
⇒ 80
Number of people in Bus 1 just after Station 2 = 20% of 300
⇒ (1/5) × 300
⇒ 1 × 60
⇒ 60
Difference of people in both buses = 80 – 60 = 20
∴ The difference of people in Bus 1 and Bus 2 just after Station 2 is 20.
Bar Graph Question 5:
Comprehension:
Direction: Study the following data carefully and answer the following questions.
The bar graph represents the percentage of people present in the bus just after every station.
What is the average number of passengers present in Bus 2 from Station1 to Station 4 if total capacity of Bus 2 is 150 approximately?
Answer (Detailed Solution Below)
Bar Graph Question 5 Detailed Solution
Given:
The people present in Bus 2,
In station 1 = 30%
In station 2 = 20%
In station 3 = 40%
In station 4 = 60%
Total capacity = 150
Concept used:
Average = Sum of passengers/Number of station
Calculation:
Average = {(30% + 20% + 40% + 60%) × 150}/4
⇒ (150/100) × (150/4)
⇒ (3/2) × (75/2)
⇒ 225/4
⇒ 56.25
∴ The average of passengers in Bus 2 from Station 1 to Station 4 is approximately 56.25.
Top Bar Graph MCQ Objective Questions
Directions: The data for family sizes in a town is given below. Based on the bar graph, answer the question given below:
Calculate the average family size from the given data.
Answer (Detailed Solution Below)
Bar Graph Question 6 Detailed Solution
Download Solution PDFCalculation:
Number of families having 1 member = 5
Total members = 5
Number of families having 2 members = 30
Total members = 60
Number of families having 3 members = 45
Total members = 135
Number of families having 4 members = 40
Total members = 160
Number of families having 5 members = 25
Total members = 125
Number of families having 6 members = 5
Total members = 30
So, the total membes in all types of families = 5 + 60 + 135 + 160 + 125 + 30 = 515
Total number of families = 5 + 30 + 45 + 40 + 25 + 5 =150
The average family size = 515 / 150 = 3.4
Hence, option 3 is correct.
The given data shows the registration of bikes and total vehicles (in thousands) for 6 months in 2017 in City X.
Note: In the chart, the first number represents bikes and the second number represents total vehicles.
Based on the given data, the increase in the registration of vehicles other than bikes in April 2017 in comparison of Jan 2017 is _______.
Answer (Detailed Solution Below)
Bar Graph Question 7 Detailed Solution
Download Solution PDFNumber of registration of vehicles other than bikes in January 2017 = 27,000 - 21,000 = 6,000
Number of registration of vehicles other than bikes in April 2017 = 35,000 - 20,000 = 15,000
∴ the increase in the registration of vehicles other than bikes in April 2017 in comparison of Jan 2017 = 15,000 - 6,000 = 9,000
Directions: The data on family sizes in a town is given below. Based on the figure, answer the questions below:
]
The fraction of families with a size less than the average family size is
Answer (Detailed Solution Below)
Bar Graph Question 8 Detailed Solution
Download Solution PDFCalculation:
Number of families having 1 member = 5
Total members = 5
Number of families having 2 member = 30
Total members = 60
Number of families having 3 member = 45
Total members = 135
Number of families having 4 member = 40
Total members = 160
Number of families having 5 member = 25
Total members = 125
Number of families having 6 member = 5
Total members = 30
So, the total members in all types of families = 5 + 60 + 135 + 160 + 125 + 30 = 515
Total number of families = 5 + 30 + 45 + 40 + 25 + 5 =150
The average family size = 515 / 150 = 3.4
The families with size less than the average family size are as follows:
Number of families having 1 member = 5
Number of families having 2 member = 30
Number of families having 3 member = 45
So, the total number of families with size less than the average family size = 80
The total number of families = 150
The fraction of families with size less than the average family size = 80 / 150 = 8 / 15
Hence, option 2 is correct.
The given bar chat represents the Televisions Sets (TV) manufactured (in thousands) and the respective percentage of those TV Sets sold by five different companies A, B, C, D and E in 2015.
Study the chart carefully and answer the question that follows.
What is the ratio of the number of TV sets sold by company A to that of company B in 2015?
Answer (Detailed Solution Below)
Bar Graph Question 9 Detailed Solution
Download Solution PDFCalculation:
The number of TV sets sold by company A = 64 × 75%
⇒ 48
The number of TV sets sold by company B = 90 × 64%
⇒ 57.6
Ratio = 48 : 57.6
⇒ 5 : 6
∴ Required answer is 5 : 6.
Based on the bar graph given, calculate the approximate percentage increase in sales of mobile phones from 2004 to 2008.
Answer (Detailed Solution Below)
Bar Graph Question 10 Detailed Solution
Download Solution PDFCalculation:
Percentage increase in sales of mobile phones in 2004 = 35
Percentage increase in sales of mobile phones in 2008 = 70
Percentage increase in sales of mobile phones from 2004 to 2008 = (70 – 35)/35 × 100
⇒ 35/35 × 100
⇒ 100%
∴ The required percentage is 100%
The following bar chart represents the gross amount (in Rs. crores) and total cost (Rs. crores) of a firm.
In order to make a profit of 25%, what should the gross amount have been (in Rs. crores) in 2019-2020, if the total cost remained the same?
Answer (Detailed Solution Below)
Bar Graph Question 11 Detailed Solution
Download Solution PDFCalculation:
⇒ 6500 + 6500 × 25/100
⇒ 6500 + 1625
⇒ 8125
The gross amount should be 8125 (in Rs. crores) in 2019-2020, if the total cost remained the same.
The given bar graph shows the income and expenditure (in crores Rs.) of a company over 5 years, from 2014 to 2018. Study the bar graph and answer the question that follows.
In which of the following years is the ratio of income to expenditure the minimum?
Answer (Detailed Solution Below)
Bar Graph Question 12 Detailed Solution
Download Solution PDFGiven data:
|
Year |
Income |
Expenditure |
|
2014 |
225 |
175 |
|
2015 |
280 |
250 |
|
2016 |
325 |
275 |
|
2017 |
350 |
300 |
|
2018 |
350 |
325 |
Calculations:
Ratio of Income to expenditure for respective years-
|
Year |
Income |
Expenditure |
\(Income\over Expenditure\) |
|
2014 |
225 |
175 |
225 /175 = 1.29 |
|
2015 |
280 |
250 |
280 / 250 = 1.12 |
|
2016 |
325 |
275 |
325 / 275 = 1.18 |
|
2017 |
350 |
300 |
350 / 300 = 1.16 |
|
2018 |
350 |
325 |
350 / 325 = 1.08 |
∴ The income-expenditure ratio is the minimum in the year 2018.
Comprehension:
Direction: Study the graph and answer the following questions :
The maximum rise in the production of raw wool with respect to previous year :
Answer (Detailed Solution Below)
Bar Graph Question 13 Detailed Solution
Download Solution PDFCalculation:
Rise in 2015-16 = 53 – 51 = 2
Rise in 2016-17 = 65 – 53 = 12
Rise in 2017-18 = 76 – 65 = 11
Rise in 2019-20 = 68 – 58 = 10
Rise in 2020-21 = 73 – 68 = 5
∴ Maximum rise in production of wool with respect to previous year is in 2016-17
The given histogram shows the heights of 232 students of an athletic club and their numbers.
Study the histogram carefully and answer the questions that follows.
If the histogram is to be presented by a line diagram, what would be the starting point and the end point of the line diagram?
Answer (Detailed Solution Below)
Bar Graph Question 14 Detailed Solution
Download Solution PDFGiven:-
Athletic club of 232 members and their height's frequency.
Concept used:-
Frequency Polygon:- A frequency polygon is a graph constructed by using lines to join the midpoints of each interval or bin. The heights of the points represent the frequencies. A frequency polygon can be created from the histogram or by calculating the midpoints of the bins from the frequency distribution table.
Formula Used:
Class size = Upper limit - Lower limit
Calculation:
From histogram -
Class size = Upper limit - Lower limit
Class size = 125 - 120 = 5
∴ Mid point of a class = 5/2 = 2.5
So, Starting point of Line graph -
X - co-ordinate = 120 - 2.5 = 117.5
Y - co-ordinate = frequency of point = 0
∴ Starting point = (117.5,0)
End point of Line graph -
X - co-ordinate = 170 + 2.5 = 172.5
Y - co-ordinate = frequency of point = 0
∴ End point = (172.5,0)
∴ Required points are (117.5,0) and (172.5,0).
The following bar graph shows the number of coolers sold by shopkeepers A and B in different years. Study the graph and answer the question that follows.
The total number of coolers sold by shopkeeper B in 1995 and 1998 together is approximately what percentage more/less than the total number of coolers sold by the shopkeeper A in 1996 and 1997 together ?
Answer (Detailed Solution Below)
Bar Graph Question 15 Detailed Solution
Download Solution PDFGiven:
B(1995 + 1998) = 1620 + 1600
A(1996 + 1997) = 1590 + 1750
Solution:
The total number of coolers sold by shopkeeper B in 1995 and 1998 = 1620 + 1600 = 3220
The total number of coolers sold by shopkeeper A in 1996 and 1997 = 1590 + 1750 = 3340
difference = 3220 - 3340 = -120
⇒ less
Required percentage = 120/3340 x 100 = 3.5% ~ 4% less
Hence, the correct option is 2.