Tabulation and Pie Chart MCQ Quiz - Objective Question with Answer for Tabulation and Pie Chart - Download Free PDF

The number of candidates applied for SSC exam from Kerala in 2019 = 45000 × (19/100) × (110/100 = 9405

The number of candidates applied for SSC exam from MP in 2019 = 45000 × (16/100) × (125/100) = 9000

Difference = 9405 – 9000 = 405

The number of candidates applied for SSC exam from Bihar in 2019 = 45000 × (21/100) × (120/100) = 11340

The number of candidates applied for SSC exam from Rajasthan in 2019 = 45000 × (10/100) × (128/100) = 5760

Let the number of candidates applied for the SSC exam from UP in 2018 be 12x and the number of candidates applied for the SSC exam from MP in 2018 be 16x.

So, the number of candidates applied for SSC exam from UP in 2019 = 12x × 114/100 = 13.68x

And the number of candidates applied for SSC exam from MP in 2019 = 16x × 125/100 = 20x

The number of candidates applied for SSC exam from Rajasthan in 2018 = 45000 × (10/100) = 4500

The number of candidates applied for SSC exam from MP in 2019 = 45000 × (16/100) × (125/100) = 9000

The number of candidates applied for SSC exam from Bihar in 2019 = 45000 × (21/100) × (120/100) = 11340

The number of candidates applied for SSC exam from Jharkhand in 2019 = 45000 × (22/100) × (115/100) = 11385

Given:

There is the percentage of students in five schools in the given pie chart and the table shows the ratio of boys and girls in each school.

Concept used:

The total angle of a pie chart = 360°

Calculation:

Let, the total number of students = 100

So, the total students of each schools are:

A = 28; B = 15; C = 24; D = 18; E = 15

Then, the total number of girl student in school B = (2/5) × 15 = 6

The total number of girl student in all schools = [(3/7) × 28 + (2/5) × 15 + (5/8) × 24 + (1/3) × 18 + (4/5) × 15]

= 12 + 6 + 15 + 6 + 12

= 51

The angle = \(\frac{Number of girls in school B}{Total number of girls} \times 360\)

⇒ (6/51) × 360 = 42.35...° ≈ 42° (the nearest integer)

∴ The measure of the sector angle (to the nearest integer) will be 42°

Calculation:

The number of illiterate people in Goa is , 2/5 × 315000 × 12/100 =15120

The number of illiterate people in MP is , 4/5 × 315000 × 20/100  =50400

Total is 50400 + 15120 = 65520

∴ The correct option is 1

Calculation:

Population of Goa in the year 1998 = 32760000 × 12%

⇒ 39,31,200

Population of Goa in the year 1997 = 39,31,200 × 100/120

⇒ 32,76,000

Population of Arunachal Pradesh in the year 1998 = 32760000 × 25%

⇒ 81,90,000

Population of Arunachal Pradesh in the year 1997 = 81,90,000 × 100/110

⇒ 81,90,0000/11

Ratio = 3276000 : 81,90,0000/11

⇒ 11 : 25

∴ The required answer is 11 : 25.

Given:

Calculation: 

Total percentage as per the pie chart is 100%

⇒ 100% = 32760000

⇒ 1% = 327600

As per the question, 

The population of Arunachal Pradesh,

⇒ 25 × 327600

The population of Uttar Pradesh, 

⇒ 15 × 327600

Now female in Arunachal Pradesh is 3/8

and female in Uttar Pradesh is 2/5

⇒  25 × 327600 × 3/8 = 15 × 327600 × 2/5

⇒ 25:16

∴ The ratio of the number of females in Arunachal Pradesh to the number of females in Uttar Pradesh was 25 ∶ 16.

Given:

In 150 seats, the occupied seats for First class AC class on Monday = 145

In 150 seats, the occupied seats for First class AC class on Tuesday = 120

In 150 seats, the occupied seats for First class AC class on Wednesday = 130

In 150 seats, the occupied seats for First class AC class on Thursday = 125

In 150 seats, the occupied seats for First class AC class on Friday = 130

Calculation:

According to the question,

The total vacant seats for First class AC class from Monday to Friday:

⇒ (150 – 145) + (150 – 120) + (150 – 130) + (150 – 125) + (150 – 130)

⇒ 5 + 30 + 20 + 25 + 20 = 100

Vacant seats for first class AC class on Thursday = 150 - 125 = 25

As per the concept used:

100 → 360°

⇒ 25 → (360° × 25)/100

⇒ 25 → 90°

Calculation:

Now, the number of males in Bihar in the year 1998

⇒ 32760000 × 11% × 3/(3 + 4)

⇒ 1544400

∴ The number of males in Bihar in the year 1998 is 15,44,400.

Calculation:

Total number of students in section E = 300 × 14/100 = 42

Number of boys in section E = 42 × 3/7 = 18

Total number of students in section C = 300 × 19/100 = 57

Number of girls in section C = 57 - 34 = 23

∴ the ratio of number of boys in section E to the number of girls in section C is = 18 : 23

Calculation:

Number of girls in institute A = 3600 × 18% × 5/(7 + 5) = 270

Number of girls in institute B = 3600 × 24% × 5/(4 + 5) = 480

Number of girls in institute E = 3600 × 16% × 7/(5 + 7) = 336

The average number of girls in Institutes A, B, and E = (270 + 480 + 336)/3 = 362

Number of boys in institute D = 3600 × 22% × 5/(5 + 4) = 440

Now, The difference between the average number of girls in Institutes A, B and E and the number of boys in Institute D

⇒ 440 - 362

⇒ 78 = x

∴ The value of x lies between 70 and 80.

Calculation:

Let total number of students in the schools be 100

Number of students in school D = 100 × 18%

⇒ 18

Number of girls in school D = 18 × (1/3)

⇒ 6

Number of students in school B = 100 × 15%

⇒ 15

Number of boys in school B = 15 × (3/5)

⇒ 9

Difference = 9 - 6

⇒ 3

Required % = (3/9) × 100

⇒ 33.33% ≈ 33%

∴ Required answer is 33%.

Traditional method:

Employees in HR = 8% of 800 = 64

⇒ Number of males in HR = 3/8 × 64 = 24

Employees in IT = 15% of 800 = 120

⇒ Number of males in IT = 2/5 × 120 = 48

Employees in Accounts = 25% of 800 = 200

⇒ Number of males in Accounts = 3/10 × 200 = 60

Employees in Marketing = 22% of 800 = 176

⇒ Number of males in Marketing = 7/11 × 176 = 112

Employees in Production = 30% of 800 = 240

⇒ Number of males in Production = 5/8 × 240 = 150

∴ Total number of males = 24 + 48 + 60 + 112 + 150 = 394

Alternate Method

The percentage of male employees = 8 × 3/8 + 15 × 2/5 + 25 × 3/10 + 22 × 7/11 + 30 × 5/8

= 3 + 6 + 7.5 + 14 + 18.75

= 49.25%

• Total no. of males

= 49.25% of 800

= (800 × 49.25)/100

= 394