Question
Download Solution PDFTime constant of an R-L circuit is given by
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
An L-R Series Circuit consists basically of an inductor of inductance L, connected in series with a resistor of resistance R. The resistance “R” is the resistive value of the wire turns or loops that go into making up the inductors coil.
Time constant (τ) –
The time constant is defined as the time required for the circuit to reach 63.2% of the final value (steady-state value).
Additional Information
Derivation for Time constant for RL Circuit:
Consider series RL circuit,
Applying KVL to the circuit,
\(\large{V=Ri(t)+L\frac{di(t)}{dt}}\)
Taking Laplace Transformation of the equation at both sides,
\(\large{\frac{V}{s}=L[sI(s)-i(0+)]+RI(s)}\)
i(0+) = 0 (Since the current just after the switch is on, the current through the inductor will be zero.)
\(\large{\frac{V}{s}=LsI(s)+RI(s)}\)
\(\large{I(s)=\frac{V}{L} \frac{1}{s(s+R/L)}}\)
Now taking Inverse Laplace Transform to the above equation,
\(\large{i(t)=\frac{V}{R}[1-e^{\frac{-Rt}{L}}]=\frac{V}{R}[1-e^{\frac{-t}{T}}]}\)
Where, \(\large{T=\frac{L}{R}}\)
In the RL circuit, at t = T sec, the current becomes 63.2% of its final steady-state value.
Last updated on May 8, 2025
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