In an AC circuit, v = 20 sin (ωt + 60°) V and i = 10 sin (ωt + 30°) A. What are the apparent and reactive powers, respectively?

This question was previously asked in
MPPGCL JE Electrical 28 April 2023 Shift 3 Official Paper
View all MPPGCL Junior Engineer Papers >
  1. 100 VA and 100 VAr
  2. 100 VA and 50 VAr
  3. 200 VA and 50 VAr
  4. 200 VA and 100 VAr

Answer (Detailed Solution Below)

Option 2 : 100 VA and 50 VAr
Free
MPPGCL JE Electrical Full Test 1
3.9 K Users
100 Questions 100 Marks 120 Mins

Detailed Solution

Download Solution PDF

Concept

The apparent power in an AC circuit is given by:

\(S=V_{rms}I_{rms}\)

The active power in an AC circuit is given by:

\(P=V_{rms}I_{rms}\space cos(\theta_v-\theta_i)\)

The reactive power in an AC circuit is given by:

\(Q=V_{rms}I_{rms}\space sin(\theta_v-\theta_i)\)

Calculation

Given, v = 20 sin (ωt + 60°) V

i = 10 sin (ωt + 30°) A

\(S={20\over \sqrt{2}}\times{10\over \sqrt{2}}\)

S = 100 VA

\(Q={20\over \sqrt{2}}\times{10\over \sqrt{2}}\times sin(60-30)\)

Q = 50 VAr

Latest MPPGCL Junior Engineer Updates

Last updated on May 29, 2025

-> MPPGCL Junior Engineer result PDF has been released at the offiical website.

-> The MPPGCL Junior Engineer Exam Date has been announced.

-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.

-> Candidates can apply online from 23rd December 2024 to 24th January 2025.

-> The selection process includes a Computer Based Test and Document Verification.

-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.

More Sinusoidal Steady State Analysis Questions

Get Free Access Now
Hot Links: teen patti master 51 bonus teen patti gold new version teen patti palace teen patti club