Question
Download Solution PDFAn R-L series circuit, where R = 10 Ω and L = 0.056 H, is connected to an AC supply of frequency 50 Hz. The magnitude of impedance of the circuit is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The impedance of a series RL circuit is given by:
\(Z=R+jX_L\)
\(Z=R+jω L\)
The magnitude of the impedance is:
\(\left | Z \right |=\sqrt{R^2+X_L^2}\)
Calculation
Given, R = 10 Ω and L = 0.056 H
f = 50 Hz
ω = 2πf = 314 radian
XL = ω × L
XL = 314 × 0.056 = 17.584 Ω
\(\left | Z \right |=\sqrt{(10)^2+(17.584)^2}\)
\(\left | Z \right |=20.23\space \Omega\)
Last updated on May 29, 2025
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