The Norton’s equivalent current (IN) between A and B for the circuit is:

F1 Vinanti Engineering 31.12.22 D6

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SSC JE Electrical 16 Nov 2022 Shift 3 Official Paper
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  1. 0 A
  2. 4 A
  3. 2.5 A
  4. 1 A

Answer (Detailed Solution Below)

Option 3 : 2.5 A
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Detailed Solution

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The correct answer is option 3): (2.5 A)

Concept:

Norton’s Theorem states that “Any linear circuit containing several energy sources and resistances can be replaced by a single constant current source in parallel with a single resistor “.

F1 U.B Madhu 31.12.19 D 12

Steps to follow for Norton’s Theorem:

  • Calculate Norton’s current source by removing the load resistor from the original circuit and replacing it with a short circuit. Calculating the current through a shorted wire.
  • Calculating the Norton resistance by removing all power sources in the original circuit (voltage sources shorted and current sources open).
  • Calculating total resistance between the open connection points.
  • Draw the Norton equivalent circuit, with the Norton current source in parallel with the Norton resistance.
  • The load resistor re-attaches between the two open points of the equivalent circuit.

Calculation:

Given

F1 Vinanti Engineering 31.12.22 D6

Remove the load resistor 

R = 4 Ω 

V = 10 V

IN = \(10 \over 4\)

= 2.5 A

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