The admittance of an electric circuit is represented by Y = (3 + j4). What is the value of resistance in this circuit? 

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SSC JE Electrical 9 Oct 2023 Shift 3 Official Paper-I
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  1. \(\frac{2}{25}\Omega\)
  2. \(\frac{4}{25}\Omega\)
  3. \(\frac{1}{25}\Omega\)
  4. \(\frac{3}{25}\Omega\)

Answer (Detailed Solution Below)

Option 4 : \(\frac{3}{25}\Omega\)
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Detailed Solution

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Concept:

Impedance (Z) = \({1\over Admittance (Y)}\)

Z = R + jX

where, R = Resistance & X = Reactance

Y = G + jB

where, G = Conductance & B = Susceptance

Calculation:

Given, Y = 3 + j4

\(Z={1\over 3+j4}\)

\(Z={1\over 3+j4}\times{3-j4\over 3-j4}\)

\(Z={1\over 25}(3-j4)\)

Resistance, R = \(\frac{3}{25}\Omega\)

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