Question
Download Solution PDFIn a pure inductive circuit if the supply frequency is reduced to 1/10th of the previous value, the current will be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The current in a purely inductive circuit is given by:
\(I={V\over X_L}\)
\(I={V\over ω L}\)
where, I = Current
V = Voltage
ω = Frequency
L = Inductance
Explanation
From the above expression, the current is inversely proportional to the frequency.
\(I\space \alpha \space {1\over \omega }\)
In a purely inductive circuit, if the supply frequency is reduced to 1/10th of the previous value, the current will be ten times high.
Last updated on May 29, 2025
-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.