Question
Download Solution PDFఒకవేళ Δ ABC~Δ FDE అంటే AB = 9 సెం.మీ, AC = 11 సెం.మీ, DF = 16 సెం.మీ మరియు DE = 12 సెం.మీ, అప్పుడు BC యొక్క పొడవు:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చినది:
AB = 9 సెం.మీ, AC = 11 సెం.మీ, DF = 16 సెం.మీ మరియు DE = 12 సెం.మీ
ఉపయోగించిన భావన:
రెండు త్రిభుజాలు సారుప్యాలుగా ఉన్నప్పుడు, వాటి సంబంధిత కోణాలు సమానంగా ఉంటాయి మరియు వాటి సంబంధిత భుజాలు అనులోమానుపాతంలో ఉంటాయి.
గణన:
ΔABC ~ ΔFDE వలె
కాబట్టి, AB/DF = BC/DE = AC/FE
ఇప్పుడు,
AB/DF = BC/DE
⇒ 9/16 = BC/12
⇒ BC = (9 × 12)/16
⇒ BC = 27/4
⇒ BC = \(6\frac{3}{4}\) సెం.మీ
∴ BC పొడవు \(6\frac{3}{4}\) .
Last updated on Jun 13, 2025
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