जर 4 tan θ = 3, तर\(\frac{4 \sin θ-\cos θ+1}{4 \sin θ+\cos θ-1}=\) _________.

Question

Question

This question was previously asked in

SSC CGL 2022 Tier-I Official Paper (Held On : 07 Dec 2022 Shift 4)

Answer 1

दिले आहे:

4 tan θ = 3

गणना:

F3 SSC Arbaz 24-05-2023 Himanshu D1

पायथागोरसचे प्रमेय लागू करणे

AC² = AB² + BC²

AC² = 3² + 4²

AC = 5

sinθ = 3/5

cosθ =4/5

\(\frac{4 \sin θ-\cos θ+1}{4 \sin θ+\cos θ-1}\)

वरील मूल्ये

⇒ \(\frac{4 \times 3/5-4/5+1}{4 \times 3/5+4/5-1}\)

⇒ \(\frac{12/5-4/5+1}{12/5+4/5-1}\) = \(\frac{(12-4+5)/5}{(12 +4 - 5)/5}\)

⇒ \(\frac{13/5}{11/5}\) = \(\frac{13}{11}\)

∴ पर्याय 4 हे बरोबर उत्तर आहे.

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