Question
Download Solution PDFIn a triangle ABC tan A + tan B + tan C = k What is the value of cot A cot B cot C?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
In triangle ABC, A + B + C = π
⇒ tan(A + B + C) = tanπ = 0
⇒ \(\frac{tan A+tan B+ tan C - tan A tan Btan C}{1- tan A.tan B- tan B.tan C - tan C.tan A} = 0\)
⇒ tanA. tanB. tanC = tanA + tanB + tanC
⇒ cotA. cotB. cotC = \(\frac{1}{tan A+tan B+tan C }\)
= 1/k
∴ Option (b) is correct
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