Question
Download Solution PDFIn the following circuit, if I1 = 10 A, I2 = 15 A and I3 = 20 A, find the total current IT.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFKirchhoff’s Current Law (KCL): It states that the algebraic sum of currents entering a node or closed boundary is zero.
Mathematically, KCL implies that
\(\mathop \sum \limits_{n = 1}^N {i_n} = 0 \)
Where N is the number of branches connected to the node
And in is the nth current entering or leaving the node.
By this law current entering a node may be regarded as positive and current leaving a node may be regarded as negative or vice-versa.
Considered the node in the figure shown below, in which i1, i3, and i5 are incoming current and i2, i4, and i6 are outgoing current.
Applying KCL gives,
i1 + i3 + i5 = i2 + i4 + i6
Hence, the sum of currents entering a node is equal to the sum of the currents leaving the node.
Note: KCL is based on the conservation of charge.
Application:
Applying KCL to the circuit,
IT + I2 = I1 + I3
Given,
I1 = 10 A, I2 = 15 A and I3 = 20 A
Hence,
IT = 10 + 20 - 15 = 15 A
Last updated on May 12, 2025
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