Question
Download Solution PDFIn the circuit shown below, what is the current I of sinusoidal source?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In a parallel RL circuit, current (I) is given by:
I = IR - jIL
\(I = {\sqrt{I_R^2\space+\space I_L^2}}\)
The power factor is given by:
cos ϕ = cos (tan-1\(( {I_L \over I_R})\))
Calculation:
Given, IR = 12 A
IL = 16 A
\(I = {\sqrt{(12)^2\space+\space (16)^2}}\)
I = 20 A
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