In a single-phase transformer, the ratio of transformation is 2 and the secondary resistance is 0.24 Ω. Find the resistance of secondary in terms of primary.

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HPCL Engineer Electrical 01 Nov 2022 Official Paper
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  1. 0.6 Ω 
  2. 0.48 Ω 
  3. 0.12 Ω 
  4. 0.06 Ω 

Answer (Detailed Solution Below)

Option 4 : 0.06 Ω 
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Detailed Solution

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The correct answer is option 4):(0.06 Ω )

Concept:

Turns Ratio =  \(N_1\over N_2\)

Transformation Ratio (K)= \(N_2\over N_1\)

Where

N1 = number of turns in the primary winding of the transformer

N2 = number of turns in the secondary winding of the transformer The resistance offered by secondary winding in the terms of primary is

R2' = \(R_2\over (K)^2\)

Where

R2 = Resistance connected across the secondary winding.

Calculation:

K = 2

R2 = 0.24 Ω 

R2' = \(R_2\over (K)^2\)

\(0.24 \over 4\)

= 0.06 Ω 

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