Question
Download Solution PDFFind 'Req' in the given circuit.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 3):(56 Ω )
Concept:
Two resistors R1 and R2 are connected in series the Req = R1 + R2 Ω
Two resistors R1 and R2 are connected in parallel Req = ( \(1\over R_1\) + \(1 \over R_2\))-1 Ω
Calculation:
Given
In circuit 52 Ω and 28 Ω resistors are series so the Rt = 52 +28 = 80 Ω
The 80 Ω and 20 Ω are parallel so the Rt1 = ( \(1 \over 80\) + \(1 \over 20\))-1 = 16 Ω
Now
15 Ω,16 Ω, 25 Ω resistors are connected in series so Req = 15 +16 + 25 = 56 Ω
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