Question
Download Solution PDFFor a single phase transformer, the maximum efficiency occurs at 75% of the load, then \(\rm \frac{iron \ loss \ at\ full \ load }{copper \ loss \ at\ full \ load}=?\)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 4): \(\frac{9}{16}\)
Concept:
The transformer will give the maximum efficiency when its copper loss is equal to the iron loss. Efficiency is maximum at some fraction x of full load.
\(x = \sqrt {\frac{{{W_i}}}{{{W_{cu}}}}}\)
where
x is the efficiency
Wi = iron losses in watts
Wcu = copper losses in watts
Calculation:
Given
x = 0.75
\(W_i \over W_c\) = (0.75)2
= ( \(75 \over 100\))2
= ( \(3 \over 4\) )2
= \(9 \over 16\)
Last updated on May 9, 2025
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