निम्नलिखित में से कौन सी समीकरण प्रगामी तरंग का निरूपण करती है?

  1. y = Aexcos(ωt - θ)
  2. \({\rm{y = A}}{{\rm{e}}^{{\rm{ - }}{{\rm{x}}^{\rm{2}}}}}{\rm{cos}}\left( {{\rm{vt + \theta }}} \right)\)
  3. y = A sin (15x - 2t)
  4. y = A sin x cos ωt

Answer (Detailed Solution Below)

Option 3 : y = A sin (15x - 2t)
Free
JEE Main 04 April 2024 Shift 1
12.2 K Users
90 Questions 300 Marks 180 Mins

Detailed Solution

Download Solution PDF

CONCEPT:

A wave in which the positions of maximum and minimum amplitude travel through the medium is known as a traveling wave. It is written as;

y = A sin(kx-\(\omega\)t) ----(1)

Here we have A as amplitude,\(\omega\) as angular frequency, and k is the propagation constant.

EXPLANATION:

According to the traveling wave equation, we have;

y = A sin(kx-\(\omega\)t)

Therefore option 3) is matching with equation 1) we have;

y = Asin (15x - 2t)

Here, A is the amplitude, k = 15 and \(\omega\) = 2 rad/sec.

Hence, option 3) is the correct answer.

Latest JEE Main Updates

Last updated on May 23, 2025

-> JEE Main 2025 results for Paper-2 (B.Arch./ B.Planning) were made public on May 23, 2025.

-> Keep a printout of JEE Main Application Form 2025 handy for future use to check the result and document verification for admission.

-> JEE Main is a national-level engineering entrance examination conducted for 10+2 students seeking courses B.Tech, B.E, and B. Arch/B. Planning courses. 

-> JEE Mains marks are used to get into IITs, NITs, CFTIs, and other engineering institutions.

-> All the candidates can check the JEE Main Previous Year Question Papers, to score well in the JEE Main Exam 2025. 

More The speed of a travelling wave Questions

More Waves Questions

Get Free Access Now
Hot Links: teen patti master 2025 teen patti real cash all teen patti master teen patti game paisa wala