Question
Download Solution PDFComprehension
निर्देश : निम्नलिखित प्रश्नों के लिए निम्नलिखित पर विचार करें:
परवलय y2 = kx और रेखा x = k, जहाँ k > 0 है, द्वारा परिबद्ध क्षेत्रफल 4/3 वर्ग इकाई है।
k का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFव्याख्या:
दिया गया है:
परवलय y2 = kx और रेखा x = k, जहाँ k > 0, द्वारा परिबद्ध क्षेत्रफल 4/3 वर्ग इकाई है
परिबद्ध क्षेत्रफल = 4/3 वर्ग इकाई
= \(2 \int_0^kydx\)
⇒ 4/3 = \(2 \int_0^k\sqrt k \sqrt xdx\)
⇒1 = k2
⇒ k = ±1 (चूँकि k>0)
⇒ k = 1
∴ विकल्प (b) सही है।
Last updated on May 30, 2025
->UPSC has released UPSC NDA 2 Notification on 28th May 2025 announcing the NDA 2 vacancies.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced for cycle 2. The written examination will be held on 14th September 2025.
-> Earlier, the UPSC NDA 1 Exam Result has been released on the official website.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.