त्रिज्या के बराबर ऊँचाई और 5 सेमी तिर्यक ऊँचाई वाले एक शंकु का आयतन क्या है?

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SSC CGL 2023 Tier-I Official Paper (Held On: 17 Jul 2023 Shift 1)
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  1. \( \frac{125 \pi}{12 \sqrt{3}} \mathrm{~cm}^3 \)
  2. \( \frac{125 \pi}{6 \sqrt{3}} \mathrm{~cm}^3 \)
  3. \( \frac{125 \pi}{12 \sqrt{2}} \mathrm{~cm}^3 \)
  4. \( \frac{125 \pi}{6 \sqrt{2}} \mathrm{~cm}^3\)

Answer (Detailed Solution Below)

Option 4 : \( \frac{125 \pi}{6 \sqrt{2}} \mathrm{~cm}^3\)
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Detailed Solution

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दिया गया है:

शंकु की त्रिज्या और ऊँचाई समान है।

तिर्यक ऊँचाई = 5 सेमी

प्रयुक्त सूत्र:

शंकु का आयतन = (1/3) π r2 h

तिर्यक ऊँचाई = √(h2 + r2

जहाँ,

r = शंकु की त्रिज्या

h = शंकु की ऊँचाई 

= तिर्यक ऊँचाई 

गणना:

माना शंकु की त्रिज्या और ऊँचाई x है।

5 = √(x2 + x2

x = 5/√2

शंकु का आयतन = (1/3) π r2 h

⇒ (1/3) × π × (5/√2)2 × 5/√2

⇒ (1/3) × π × (25/2) × 5/√2

⇒ 125π /6√2 सेमी3

शंकु का आयतन 125π /6√2 सेमी3 है।

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