Question
Download Solution PDFPQRS एक समचतुर्भुज है। इसकी प्रत्येक भुजा 40 सेमी है। यदि PR = 64 सेमी और QS = (8x + 8) है। तब, x का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFPR = 64 सेमी
इस प्रकार, PO = RO = 32 सेमी
QS = (8x + 8) सेमी
इस प्रकार, QO = OS = (4x + 4) सेमी
Δ SOR में –
\(S{R^2} = S{O^2} + R{O^2}\)
⇒ \({40^2} = {\left( {4{\rm{x}} + 4} \right)^2} + {\left( {32} \right)^2}\)
⇒ 402 – 322 = (4x + 4)2
⇒ 4x + 4 = 24
⇒ 4x + 4 = 24
⇒ 4x = 20
⇒ x = 5 सेमी
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