Question
Download Solution PDFदी गई आकृति में, O वृत्त का केंद्र है और ∠AOC = 140° है। ∠ABC ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
O वृत्त का केंद्र है,
∠AOC =140°
गणना:
O वृत्त का केंद्र है,
शेष चाप में एक बिन्दु D लीजिए,
∠AOC = 140°
∠AOC = 2∠ADC ( जीवा द्वारा केन्द्र पर बना कोण = समान चाप खण्ड में बना दुगुना कोण)
⇒ 140° = 2∠ADC
⇒ ∠ADC = 70°
ABCD एक चक्रीय चतुर्भुज होगा,
चक्रीय चतुर्भुज के सम्मुख कोणों का योग = 180°
⇒ ∠ABC + ∠ADC= 180°
⇒ 70° + ∠ABC = 180°
⇒ ∠ABC = 110°
∴ विकल्प 2 सही उत्तर है।
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