यदि x + y = 10 और xy = 12 है, तो x2 - xy + y2 का मान ज्ञात कीजिए।

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SSC Selection Post 2024 (Graduate Level) Official Paper (Held On: 21 Jun, 2024 Shift 3)
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  1. 74
  2. 82
  3. 64
  4. 78

Answer (Detailed Solution Below)

Option 3 : 64
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दिया गया है:

यदि x + y = 10 और xy = 12

प्रयुक्त सूत्र:

(x + y)2 = x2 + 2xy + y2

गणनाएँ:

(x + y)2 = x2 + 2xy + y2

⇒ 102 = x2 + 2xy + y2

⇒ 100 = x2 + 2(12) + y2

⇒ 100 = x2 + 24 + y2

⇒ x2 + y2 = 100 - 24

⇒ x2 + y2 = 76

हमें x2 - xy + y2 ज्ञात करना है

⇒ x2 - xy + y2 = 76 - 12

⇒ x2 - xy + y2 = 64

∴ सही उत्तर विकल्प (3) है।

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