यदि समीकरण 6x – 5y + 11 = 0 और 15x + ky – 9 = 0 का कोई हल नहीं है, तो k का मान क्या है?

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RRB ALP Previous Paper 17 (Held On: 21 Aug 2018 Shift 3)
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  1. -12.5
  2. 12.5
  3. -18
  4. 18

Answer (Detailed Solution Below)

Option 1 : -12.5
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प्रयुक्त अवधारणा:

दो चर x और y में रैखिक समीकरणों के युग्म पर विचार करें।

a1x + b1y + c1 = 0

a2x + b2y + c2 = 0

यहाँ a1, b1, c1, a2, b2, c2 सभी वास्तविक संख्याएँ हैं।

ध्यान दें कि, a12 + b12 ≠ 0, a22 + b22 ≠ 0

यदि (a1/a2) = (b1/b2) ≠ (c1/c2), तो कोई हल नहीं होगा।

गणना:

जब दो समीकरणों का कोई हल नहीं है, तब समीकरणों के समानांतर पद्धति का उपयोग करने पर,

तब,

⇒ 6/15 = -5/k

⇒ k = -25/2

⇒ k = -12.5

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