निम्नलिखित चित्र में दर्शाये गए परिपथ में 20 Ω प्रतिरोध से गुजरने वाली धारा ज्ञात कीजिए।

F1 Vinanti Engineering 08.12.23 D4

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SSC JE Electrical 4 Dec 2023 Official Paper II
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  1. 4 A
  2. 3 A
  3. 2 A
  4. 4.5 A

Answer (Detailed Solution Below)

Option 3 : 2 A
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संकल्पना:​

  • 'दो' समानांतर प्रतिरोधों के लिए धारा विभाजक नियम:

किसी भी शाखा में धारा निम्नलिखित द्वारा दी जाती है:

\(I_1 = I \times{R_2 \over R_1+R_2}\) और 

\(I_2 = I \times{R_1 \over R_1+R_2}\)

जहां I1 उस शाखा में धारा है, I कुल धारा है, R1 उस शाखा का प्रतिरोध है, और R कुल समतुल्य प्रतिरोध है।

गणना:

20 Ω पर धारा विभाजक लागू करने पर

20 Ω के परितः धारा = \(\frac{5\times \frac{40}{3}}{\frac{40}{3} +20}\) = 2A

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