Question
Download Solution PDFकिसी एक बिन्दु पर दो तरंगे दाब परिवर्तन p1 = P sin (2π νt) और p2 = P sin 2π(νt - φ) उत्पन्न करती हैं। जब φ = 1/4 हो तो इस बिन्दु पर परिणामी तरंग आयाम है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFपरिणामी तरंग का आयाम दी गई दो तरंगों का योग होगा जिसे इस प्रकार दिया जा सकता है:
∴ Ptotal = P1 + P2
∴ Ptotal = P sin (2π vt) + P sin 2π(vt - ϕ )
∴ Ptotal = P [ sin (2π vt) + P sin 2π(vt - ϕ)]
∴ Ptotal = P [ 2 cos( \(\frac{2π vt + 2π(vt-ϕ)}{2}\)) sin (\(\frac{2π vt -2π(vt-ϕ)}{2}\))]
∴ Ptotal = P [ 2 cos (πϕ) ⋅ sin (ϕπ) ]
∴ Ptotal = P [ sin (2πϕ)]
∴ Ptotal = P (0)
∴ Ptotal = 0
Last updated on May 5, 2025
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