किसी एक बिन्दु पर दो तरंगे दाब परिवर्तन p1 = P sin (2π νt) और p2 = P sin 2π(νt - φ) उत्पन्न करती हैं। जब φ = 1/4 हो तो इस बिन्दु पर परिणामी तरंग आयाम है:

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  1. 2P
  2. P
  3. P\(\sqrt{2}\,\)
  4. 0

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Option 4 : 0
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परिणामी तरंग का आयाम दी गई दो तरंगों का योग होगा जिसे इस प्रकार दिया जा सकता है:

∴ Ptotal = P+ P2

∴ Ptotal = P sin (2π vt) + P sin 2π(vt - ϕ )

∴ Ptotal = P [ sin (2π vt) + P sin 2π(vt - ϕ)]

∴ Ptotal = P [ 2 cos( \(\frac{2π vt + 2π(vt-ϕ)}{2}\)) sin (\(\frac{2π vt -2π(vt-ϕ)}{2}\))]

∴ Ptotal = P [ 2 cos (πϕ) ⋅ sin (ϕπ) ]

∴ Ptotal = P [ sin (2πϕ)]

∴ Ptotal = P (0)

∴ Ptotal = 0

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