Question
Download Solution PDFएक AC परिपथ में R = 100 Ω, C = 2 μF और L = 80 mH, श्रेणीक्रम में जुड़े हुए हैं। परिपथ का गुणता कारक है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFगणना:
LC परिपथ के गुणता कारक (Q) का सूत्र इस प्रकार दिया गया है:
Q = (1 / R) × √(L / C)
जहाँ:
- R = प्रतिरोध = 100 Ω
- L = प्रेरकत्व = 80 mH = 80 × 10-3 H
- C = धारिता = 2 μF = 2 × 10-6 F
सूत्र में मान प्रतिस्थापित करने पर:
Q = (1 / 100) × √((80 × 10-3) / (2 × 10-6))
Q = (1 / 100) × √(40 × 103)
Q = (1 / 100) × 200
Q = 2
परिपथ का गुणता कारक 2 है।
Last updated on Jun 6, 2025
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