एक ट्रेन 12 सेकंड में एक खंभे को और 36 सेकंड में 170 मीटर की लंबाई के पुल को पार कर सकती है। तो ट्रेन की चाल है:

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SSC CGL Previous Paper 65 (Held On: 3 March 2020 Shift 1)
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  1. 30.75 किमी/घंटा
  2. 25.5 किमी/घंटा
  3. 32.45 किमी/घंटा
  4. 10.8 किमी/घंटा

Answer (Detailed Solution Below)

Option 2 : 25.5 किमी/घंटा
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PYST 1: SSC CGL - English (Held On : 11 April 2022 Shift 1)
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Detailed Solution

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प्रयुक्त सूत्र:

चाल = दूरी / समय

(1 मीटर/सेकंड) × (18/5) = 1 किमी/घंटा

 Shortcut Trickयदि ट्रेन 12 सेकंड में अपनी लंबाई और 170 मीटर पुल को (36 - 12 = 24) सेकंड में पार कर लेती है।

ट्रेन की चाल = [170/24] × [18/5] = 25.5 किमी/घंटा

 Alternate Method

मान लीजिए ट्रेन की लंबाई x मी है।

जैसा कि हम जानते हैं,

चाल = दूरी/समय

चाल = x/12       ---(1)

चाल = (x + 170)/36       ---(2)

समीकरण (1) और समीकरण (2) से

x/12 = (x + 170)/36

⇒ 3x = x + 170

⇒ 2x = 170

⇒ x = 170/2

⇒ x = 85 मी

समीकरण (1) से

चाल = 85/12 × (18/5) किमी/घंटा

∴ चाल = 25.5 किमी/घंटा
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