Find 'R_eq' in the given circuit.

Question

Question

This question was previously asked in

HPCL Engineer Electrical 01 Nov 2022 Official Paper

Answer 1

The correct answer is option 3):(56 Ω )

Concept:

Two resistors R1 and R₂ are connected in series the Req = R₁ + R2 Ω

Two resistors R1 and R2 are connected in parallel Req = ( + )^-1 Ω

Calculation:

Given

In circuit 52 Ω and 28 Ω resistors are series so the R_t = 52 +28 = 80 Ω

The 80 Ω and 20 Ω are parallel so the R_t1 = ( + )^-1 = 16 Ω

Now

15 Ω,16 Ω, 25 Ω resistors are connected in series so Req = 15 +16 + 25 = 56 Ω