Question
Download Solution PDFChoose the correct shear force diagram for the beam shown below -
- None of the above
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
∑M = 0
⇒ RB × L = M
⇒ \({R_B} = \frac{M}{L}\)
∑Fy = 0
⇒RA = RB \( = \frac{M}{L}\)
The SED & BMD will work like this.
Last updated on May 12, 2025
-> RSMSSB JE Answer Key 2025 has been released on 12th May, 2025 at the official website.
-> Candidates can raise objections against the RSMSSB JE Response Sheet from 17th May to 19th May, 2025.
-> The RSMSSB JE Vacancies have been revised. A total, 1355 vacancies are announced for Junior Engineer post in various departments.
-> The exam was held on 6th, 7th, 8th, 10th, 11th, and 22nd of February 2025.
-> RSMSSB Junior Engineer 2025 Notification has been released for 1226 vacancies.
-> Candidates can apply for the said post by 27th December 2024.
-> The RSMSSB Junior Engineer exam is conducted by the Rajasthan Subordinate and Ministerial Services Selection Board to recruit candidates for engineering roles in various departments.
-> The finally appointed candidates will be entitled to Pay Matrix Level 10.
-> Prepare for the exam with RSMSSB JE Previous Year Papers.