A seamless pipe is to carry a fluid under a pressure of 2 N/mm2. The thickness of the cylinder is 10 mm. Calculate the diameter of the pipe if the maximum stress allowed is 100 N/mm2.

This question was previously asked in
JKSSB JE CE 2021 Official Paper Shift 1 (Held on 30 Oct 2021)
View all JKSSB JE Papers >
  1. 0.8 m
  2. 0.9 m
  3. 1.1 m
  4. 1 m

Answer (Detailed Solution Below)

Option 4 : 1 m
Free
ST 1: JKSSB JE - Surveying
20 Qs. 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

Explanation:

Consider a thin pressure vessel having closed ends and containing fluid under a gauge pressure P. Then the walls of the cylinder will have longitudinal stress, circumferential stress and radial stress.

As shown in the figure, a point of the shell has stressed from all sides i.e. tri-axial stresses.

σ=  longitudinal stress (tensile), 

σr = radial stress (compressive), σh = circumferential stress (tensile).

As, σr <<<< σL and σh, therefore we neglect σr and assumed the bi-axial stresses.

Circumferential or hoop stress:  - (1)

Given,

Pressure = 2 N/mm2, Stress = 100 N/mm2 , t = 10 mm

from the equation (1) 

100 = (2 × d)/ (2 × 10 mm)

→ d = 1000 mm = 1 m 

Additional Information

Longitudinal or axial stress:  

where d is the internal diameter and t is the wall thickness of the cylinder

In this question, the stress is denoted by ft. Hence replacing σh with ft we get

Latest JKSSB JE Updates

Last updated on Jun 23, 2025

-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27. 

-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been released on its official website. 

-> JKSSB JE exam will be conducted on 10th August (Civil), and on 27th July 2025 (Electrical).

-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering. 

-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025. 

-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025 

-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.

-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.

-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.

More Analysis of Thin Cylinder Questions

Hot Links: teen patti wealth teen patti master plus teen patti gold real cash teen patti gold apk teen patti master apk