Thief MCQ Quiz in मल्याळम - Objective Question with Answer for Thief - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക
Last updated on Mar 17, 2025
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Thief Question 1:
A thief running at speed of ‘x’ km/h is chased by a policeman running at a speed of 10 km/h. If the thief is ahead by 100 metres, the policeman catches the thief after 3 minutes. At what speed is the thief running (‘x’ being the unknown speed)?
Answer (Detailed Solution Below)
Thief Question 1 Detailed Solution
Given:
Speed of the thief = x km/h
Speed of the policeman = 10km/h
Formula Used:
Speed = \(\frac{Distance}{Time}\)
Calculation:
Two bodies are moving in same direction then,
The relative speed between police and thief = (10 - x) km/h = (10 - x) × \(\frac{5}{18}\) m/sec.
Distance between Police and thief is = 100m
Speed = (10 - x) ×\(\frac{5}{18}\) = \(\frac{100}{3×60}\)
⇒ (10 - x) = \(\frac{100×18}{3×60×5}\) = 2
⇒ x = 10 - 2 = 8 km/h
∴ The speed of the thief is 8km/h.
Mistake Points
As the unit outside of the bracket is km/hr
Therefore the units of the final will be the same i.e.km/h
Thief Question 2:
A policeman starts chasing a thief when he was already 600 m ahead. If the policeman is running at a speed of 9 km/h and the thief at 8 km/h, then the thief would be caught at a distance of:
Answer (Detailed Solution Below)
Thief Question 2 Detailed Solution
Given:
Distance between policeman and thief = 600 m
Speed of policeman = 9 km/h
Speed of thief = 8 km/h
Formula used:
Distance = relative speed × time
Calculation:
Distance = relative speed × time
⇒ 600 = (9 - 8) × (5/18) × time
⇒ Time = (600 × 18)/5 = 120 × 18
⇒ Time = 2160 sec = (2160/3600) hours
Distance covered by policeman = 9 × (2160/3600)
⇒ (9 × 3)/5 = 5.4 km
∴ The correct answer is 5.4 km.
Thief Question 3:
A thief seeing a policeman from a distance of 400 m started running at a speed of 16 km/h. The policeman chased him immediately with a speed of 18 km/h and the thief was caught. What is the distance run by the thief before he was caught by the policeman?
Answer (Detailed Solution Below)
Thief Question 3 Detailed Solution
Given:
Distance between policeman and thief = 400 m
Speed of policeman = 18 km/h
Speed of thief = 16 km/h
Formula used:
Distance = relative speed × time
Calculation:
Distance = relative speed × time
⇒ 400 = (18 - 16) × (5/18) × time
⇒ Time = (400 × 18)/(2 × 5)
⇒ Time = 720 sec
Distance covered by thief before being caught = 16 × (5/18) × 720
⇒ 16 × 200 = 3200 m
∴ The correct answer is 3200 m.
Thief Question 4:
A thief is noticed by a policeman from a distance of 97 m. The thief starts running and the policeman chases him. The thief and the policeman run at a speed of 21 m/sec and 23 m/sec respectively. What is the time taken by the policeman to catch the thief?
Answer (Detailed Solution Below)
Thief Question 4 Detailed Solution
Given
The distance between the thief and the police is 97m
The speed of a thief is 21 m/sec
The speed of the police is 23 m/sec
Formula used
Time is taken to meet = Initial Distance / Relative Speed
Distance = speed × time
Calculation
Initial distance = 97m
Relative Speed = 23 - 21 = 2m/sec
Time is taken to catch the thief = 97/2 = 48.5 sec
∴ The policeman catches the thief in 48.5 sec.
Thief Question 5:
A thief stole jewellery from a shop at 8:15 p.m. and left on a bike at a speed of 60 km/h. The police were informed at 8:30 p.m. If the police want to arrest the thief at 9:00 p.m., what should be the minimum speed of the police jeep?
Answer (Detailed Solution Below)
Thief Question 5 Detailed Solution
Given:
Time when the thief stole the jewellery = 8:15 p.m.
Speed of thief's bike = 60 km/h
Time when police were informed = 8:30 p.m.
Formula used:
Minimum speed of police officer = \(\text {Distance between the thief and the police} \over \text{Time taken by police to reach the thief}\)
Calculation:
If the thief left at 8:15 p.m. and the police wants to catch him at 9:00 p.m., the time for which the thief was on the bike = 45 minutes = \(3 \over 4\) hours = 0.75 hours
Distance travelled by the thief = 60 km/h × 0.75 h = 45 km
Time taken by the police to reach the thief = 30 minutes = 0.5 hours
Thus, minimum speed of the police jeep should be = \(45\: \text{km} \over 0.5 \:\text{h}\) = (45 × 2) km/h = 90 km/h
∴ The minimum speed of the police jeep should be 90 km/h.
Thief Question 6:
A policeman noticed a thief at a distance of 500 metres. The policeman started running and the thief also started running at the same time. The thief is running at a speed of 15 km/h. It took 15 minutes for the policeman to catch the thief. Find the speed of the policeman (in km/h).
Answer (Detailed Solution Below)
Thief Question 6 Detailed Solution
Given:
Distance between the policeman and the thief = 500 meters
Speed of the thief = 15 km/h
Time taken by the policeman to catch the thief = 15 minutes
Formula Used:
Relative Speed = Distance / Time
Calculation:
First, convert the time taken by the policeman to hours:
Time = 15 minutes = 15 / 60 hours = 0.25 hours
Since the policeman catches the thief, we need to find the relative speed:
Relative Speed = Distance / Time
Distance = 500 meters = 500 / 1000 km = 0.5 km
Relative Speed = 0.5 / 0.25
Relative Speed = 2 km/h
Since the relative speed is the difference in speeds of the policeman and the thief:
Let Speed of the Policeman be
Relative Speed = Speed of Policeman - Speed of Thief
2 = x - 15
⇒ x = 2 + 15
⇒ x = 17 km/h
The speed of the policeman is 17 km/h.
Thief Question 7:
A thief is chased by a policeman and distance between them is 3 km. The speed of policeman is 75 km/h and the speed of the thief is 60 km/h. The policeman will be able to catch the thief when the thief would have covered the distance of ____________ km.
Answer (Detailed Solution Below)
Thief Question 7 Detailed Solution
Given:
Speed of the thief = 60 km/hr
Speed of the policeman = 75 km/hr
Formula used:
Time = Distance/Speed
Concept used:
If two bodies are moving in the same direction at u m/s and v m/s, (u > v)
Then the relative speed of the first body with respect to the second body = (u - v) m/s.
Calculation:
The relative speed between police and thief = (75 - 60) = 15 km/hr
⇒ Distance between police and thief = 3 km
⇒ Time taken = Distance/Relative Speed
⇒ Time taken = 3/15 = 1/5
⇒ Time taken = 1/5 × 60 min = 12 minutes
Distance travelled by a thief in 12 minutes = 60/60 × 12 = 12 km
The answer is 12 km.
Thief Question 8:
A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km/h and 11 km/h, respectively. What is the distance (in metres) between them after 9 minutes?
Answer (Detailed Solution Below)
Thief Question 8 Detailed Solution
Given:
Distance between thief and policeman = 200 m
Speed of the thief = 10 km/h
Speed of the policeman = 11 km/h
Time = 9 minutes
Formula Used:
Relative speed = Speed of the policeman - Speed of the thief
Distance between them after time t = Initial distance - (Relative speed × Time)
Calculation:
Relative speed = 11 km/h - 10 km/h
Relative speed = 1 km/h
Convert relative speed to m/min:
1 km/h = 1000 m / 60 min
Relative speed = 1000 / 60
Relative speed = 50/3 m/min
Time = 9 minutes
Distance covered in 9 minutes:
Distance = Relative speed × Time
Distance = (50/3) × 9
Distance = 150 m
Distance between them after 9 minutes:
⇒ 200 m - 150 m
⇒ 50 m
The distance between them after 9 minutes is 50 meters.
Thief Question 9:
A thief seeing a policeman from a distance of 300 m starts running at a speed of 10 km/h. The policeman gives chase immediately at a speed of 12 km/h and the thief is caught. What is the distance run by the thief?
Answer (Detailed Solution Below)
Thief Question 9 Detailed Solution
Given :
Speed of Policeman = 12 km/h
Speed of thief = 10 km/h
Calculation :
⇒ (300 + x)/1000 × 12 = x /1000 × 10
⇒ 300 + x/12 = x/10
⇒ 3000 + 10x = 12x
⇒ 2x = 3000
⇒ x = 1500 m = 1.5 km
∴ The correct answer is 1.5 km.
Thief Question 10:
A thief takes off on his bike at a certain speed, after seeing a police car at a distance of 250 m. The police car starts chasing the thief and catches him. If the thief runs 1.5 km before being caught and the speed of the police car is 70 km/h, then what is the speed of thief's bike (in km/h)?
Answer (Detailed Solution Below)
Thief Question 10 Detailed Solution
Given:
Distance between the thief and the police car = 250 m
Distance run by the thief before being caught = 1.5 km = 1500 m
Speed of the police car = 70 km/h = 70 × (1000/3600) m/s = 70000/3600 m/s = 350/18 m/s
Formula Used:
Time taken to catch the thief = Distance run by the thief / Speed of the thief
Distance covered by the police car = Distance between the thief and the police car + Distance run by the thief
Speed of the thief = Distance run by the thief / Time taken to catch the thief
Calculation:
Let the speed of the thief be v m/s.
Time taken to catch the thief = 1500 / v seconds
Distance covered by the police car = 250 + 1500 = 1750 m
Time taken by the police car to cover 1750 m = 1750 / (350/18) seconds
Time taken by the police car to cover 1750 m = 1750 × 18 / 350
Time taken by the police car to cover 1750 m = 90 seconds
Since both times are equal, we have:
1500 / v = 90
⇒ v = 1500 / 90
⇒ v = 16.67 m/s
Convert the speed of the thief to km/h:
Speed of the thief = 16.67 × (3600/1000) km/h
Speed of the thief = 16.67 × 3.6 km/h
Speed of the thief = 60 km/h
The speed of the thief's bike is 60 km/h.
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