Work and Wages MCQ Quiz - Objective Question with Answer for Work and Wages - Download Free PDF
Last updated on Jun 12, 2025
Latest Work and Wages MCQ Objective Questions
Work and Wages Question 1:
Three persons X, Y and Z are employed to do a piece of work. X and Y together completed
Answer (Detailed Solution Below)
Work and Wages Question 1 Detailed Solution
Given:
X and Y together completed (21/25) part of the work.
Y and Z together completed (8/25) part of the work.
All 3 agreed to complete the work for ₹3,250.
Formula used:
Let the total work = 25 units (as work is assumed to be a whole unit).
Payment is divided among X, Y, and Z in the ratio of their contributions to the work.
Calculation:
Le the work done by X, Y and Z be X , Y and Z respectively.
⇒ So, Work done by X + Y = 21 units ......(1)
⇒ Work done by Y + Z = 8 units ...........(2)
⇒ X + Y + Z = 25 .......(3)
Adding eqn (1) and (2)
⇒ X + 2Y + Z = 29 ........(4)
Subtract eqn (3) from eqn (4).
⇒ (X + 2Y + Z) - (X + Y + Z) = 29 - 25
⇒ Y = 4
So, from equation (1) ⇒ X + 4 = 21 ⇒ X = 17
From equation (2) ⇒ 4 + Z = 8 ⇒ Z = 4
⇒ Amount recived by X = 17/25 × ₹3,250 = 2210
⇒ Amount recived by Z = 4/25 × ₹3,250 = 520
⇒ Difference between amount recieved by X and Z = 2210 - 520 = ₹1,690
The correct answer is Option (3).
Work and Wages Question 2:
A alone can do a piece of work in 10 days and B alone can do the same work in 15 days. A and B agreed to complete the work for ₹30,000. With the help of C, they completed the work in 5 days. Then the amount to be paid to C is
Answer (Detailed Solution Below)
Work and Wages Question 2 Detailed Solution
Given:
A can complete the work in 10 days
B can complete the work in 15 days
Total payment = ₹30,000
A, B and C together complete the work in 5 days
C’s share is
Formula used:
Work per day = 1 / Time
Share = (Work ratio) × Total amount
Calculation:
Work per day of A = 1/10
Work per day of B = 1/15
Work per day of A + B + C = 1/5
⇒ 1/10 + 1/15 + C = 1/5
⇒ LCM = 30
⇒ 3/30 + 2/30 + C = 6/30
⇒ 5/30 + C = 6/30
⇒ C = 1/30
Now, work ratios per day:
A : B : C = 1/10 : 1/15 : 1/30
⇒ LCM = 30, so ratio becomes 3 : 2 : 1
Total ratio = 3 + 2 + 1 = 6 parts
C’s share = 1/6 × ₹30,000 = ₹5,000
A’s share = 3/6 × ₹30,000 = ₹15,000
Now check:
∴ The correct answer is Option (4).
Work and Wages Question 3:
A can do a work in 20 days, while B can do the same work in 25 days. They started the work jointly. Few days later C also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.700. What is the share of C?
Answer (Detailed Solution Below)
Work and Wages Question 3 Detailed Solution
Given:
A can complete the work in 20 days.
B can complete the work in 25 days.
All three (A, B, and C) completed the work together in 10 days.
Total payment = Rs.700.
Formula Used:
Work done by a person in one day = 1 / Number of days to complete the work.
Total work done = Work completed in 10 days.
Share of payment = (Work done by the person / Total work) × Total payment.
Calculation:
Work done by A in 1 day = 1 / 20.
Work done by B in 1 day = 1 / 25.
Work done by A and B in 1 day = (1 / 20) + (1 / 25).
Work done by A and B in 1 day = 5 / 100 + 4 / 100 = 9 / 100.
Work done by A and B in 10 days = 10 × (9 / 100) = 90 / 100.
Remaining work = Total work - Work done by A and B.
Remaining work = 1 - (90 / 100) = 10 / 100.
Work done by C = Remaining work = 10 / 100.
Total payment = Rs.700.
Share of C = (Work done by C / Total work) × Total payment.
Share of C = (10 / 100) × 700 = Rs.70.
The share of C is Rs.70.
Work and Wages Question 4:
P, Q and R can complete a work in 24, 30 and 40 days respectively. Total wage of a work is Rs. _______ . P works for ____ days alone then Q works for 4 days alone and the rest of the work is done by P, Q and R together. Difference between the wage of P and R is Rs. _______. Find which of the following is true?
Answer (Detailed Solution Below)
Work and Wages Question 4 Detailed Solution
Calculation
For option 3),
P, Q and R can complete a work in 24, 30 and 40 days respectively.
So, total work = LCM of 24, 30 and 40 = 120 unit
So, Efficiency of P, Q and R is 5, 4 and 3 respectively.
[Efficiency = total work / total number of days]
P works for 4 days alone.
So, P did 4 × 5 = 20 unit of work.
Q did 4 × 4 = 16 unit of work
Rest work 120 - 20 – 16 = 84
They together complete the work in 84 / [ 5 + 4 +3] = 7
Wage for per unit work is 3480 / 120 = 29
P did = 20 + 7 × 5 = 55 unit of work.
R did 7 × 3 = 21 unit of work
So, difference between wage P and R is [ 55 – 21] × 29 = 986
So, Option 3) is satisfy.
Work and Wages Question 5:
A can do a work in 10 days and B can do the same work in 15 days. They earn Rs. 1,500 together. How will they share this amount?
Answer (Detailed Solution Below)
Work and Wages Question 5 Detailed Solution
Given:
A can do a work in 10 days
B can do the same work in 15 days
Total earnings = Rs. 1,500
Formula used:
Share of A and B is based on their work rate.
Work rate of A = 1/10
Work rate of B = 1/15
Calculation:
Total work rate = 1/10 + 1/15 = (3 + 2)/30 = 5/30 = 1/6
Share of A = (1/10) / (1/6) × 1500 = 900
Share of B = (1/15) / (1/6) × 1500 = 600
∴ The correct answer is option 2 (Rs. 900 and Rs. 600).
Top Work and Wages MCQ Objective Questions
A and B together are supposed to do 13/15 of the work and B and C together 11/20 of the work. If the difference between wages of A and C is Rs. 7600, then the total wages of A and C is:
Answer (Detailed Solution Below)
Work and Wages Question 6 Detailed Solution
Download Solution PDFGiven:
Difference between wages of A and C = Rs. 7600
Formula Used:
Share in wages = Work done/Total work × Total wages
Calculation:
Let total work be 60 unit,
Work done by A and B = 13/15 × 60 = 52 unit
⇒ Work done by C = 60 – 52 = 8 unit
Work done by B and C = 11/20 × 60 = 33 unit
⇒ Work done by A = 60 – 33 = 27 unit
Work done by B = 60 – 27 – 8 = 25 unit
According to the question,
27 – 8 = 19 unit = 7600
⇒ 1 unit = 400
Total wages of A and C = (27 + 8) = 35 units = 35 × 400 = Rs. 14000
In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered-to with remaining meal?
Answer (Detailed Solution Below)
Work and Wages Question 7 Detailed Solution
Download Solution PDFGiven:
In a camp there is a meal for 120 men or 200 children.
Calculation:
According to the question, 150 children have taken the meal
So, 50 children left
⇒ 200 children = 120 men
⇒ 50 = 120 × (
⇒ 30 men
∴ 30men will be catered-to with remaining meal.
5 women and 9 girls earn a total of ₹18,720 in 9 days, while 9 women and 16 girls earn a total of ₹ 52,080 in 14 days. How much will 12 women and 7 girls together earn (in ₹) in 13 days?
Answer (Detailed Solution Below)
Work and Wages Question 8 Detailed Solution
Download Solution PDFGiven:
5 women and 9 girls can earn Rs.18,720 in 9 days
9 women and 16 girls earn a total of ₹ 52,080 in 14 days
Concept:
Total work = number of workers doing work × time taken to complete the work.
Calculation:
(5W + 9G) × 9 = 18,720
⇒ (5W + 9G) = 2080 ----(i)
(9W + 16G) × 14 = 52080
⇒ (9W + 16G) = 3720 ----(ii)
solving equations (i) and (ii)
⇒ 45W + 81G = 18720 ---- (iii)
⇒ 45W + 80G = 18600 ---- (iv)
by subtraction equations (iii) and (iv)
⇒ 1G = Rs. 120
Putting the value of G in equation (i)
⇒ 5W + 1080 = 2080
⇒ 5W = 1000
⇒ W = Rs.200
According to the question:
Money earned by 12 women and 7 girls in 13days
⇒ (12 × 200 + 7 × 120) × 13
⇒ (2400 + 840) × 13
⇒ 3240 × 13 = 42120
∴ The required value is 42120.
A firm reduced employees in the ratio 12 ∶ 5 in time of inflation, and the average wage per employee increased in the ratio 9 ∶ 17. By doing so, the firm saved Rs.46,000. What was the initial expenditure (in Rs) of the firm?
Answer (Detailed Solution Below)
Work and Wages Question 9 Detailed Solution
Download Solution PDFFormula Used:
Expenditure = number of employee × average wage
Calculation:
Let the number of employee of the firm be 12x and 5x pre and post reduction respectively.
and average salary be 9y and 17 y pre and post reduction respectively.
Expenditure before reduction is 12x × 9y
Expenditure after reduction is 5x × 17y
ATQ: 12x × 9y - 5x × 17y = 46000
⇒ (108 - 85)xy = 46000
⇒ 23xy = 46000
⇒ xy = 2000
Expenditure before reduction is 12x × 9y = 108 × xy = 108 × 2000 = 216000
Expenditure before reduction is Rs. 216000.
4 men and 6 women get Rs. 1600/- by doing a piece of work in 5 days, 3 men and 7 women get Rs. 1740/- by doing the same work in 6 days. In how many days 7 men and 6 women can complete the same work getting Rs. 3760/-
Answer (Detailed Solution Below)
Work and Wages Question 10 Detailed Solution
Download Solution PDFGiven:
4 men and 6 women get Rs. 1600/- by doing a piece of work in 5 days
3 men and 7 women get Rs. 1740/- by doing the same work in 6 days
7 men and 6 women can complete the same work getting Rs. 3760/-
Calculation:
Let,
M as the rate at which one man can complete the work (in Rs./day)
W as the rate at which one woman can complete the work (in Rs./day)
From the given problem, we have two equations:
4M + 6W = 1600/5 ------- (equation 1)
3M + 7W = 1740/6 ------- (equation 2)
First, multiply equation (1) by 3 and equation (2) by 4:
12M + 18W = 960 ------- (equation 3)
12M + 28W = 1160 ------- (equation 4)
Equation (4) - Equation (3)
10W = 200
⇒ W = 200 / 10 = Rs. 20/day
Substitute W into equation (1):
4M + 6 × 20 = 320
⇒ M = 200 / 4 = Rs. 50/day
Now,
Work = Rate × Time
3760 = (7M + 6W) × Time
3760 = (7 × 50 + 6 × 20) × Time
3760 = (350 + 120) × Time
3760 = 470 × Time
Time = 3760 / 470 = 8 days
∴ Required number of days = 3760/470 = 8 days.
Shortcut Trick
Calculation:
⇒
⇒
⇒
⇒ 20 m = 50 w
⇒ m : w = 5 : 2
Now, put the respective ratio in the equation:
⇒
According to the question:
⇒
⇒ 1/10 = d/80
Required number of days = 80/10 = 8 days
∴ The correct answer is 8 days.
15 persons have taken a job of digging a pond in 20 days. 5 persons have left after 10 days. Again after 5 days 5 more have left. How many days would be required to complete the job?
Answer (Detailed Solution Below)
Work and Wages Question 11 Detailed Solution
Download Solution PDFGIVEN:
Time taken by 15 people to dig the pond = 20 days
FORMULA USED:
Man – day formula
(m1 × d1 × h1)/w1 = (m2 × d2 × h2)/w2
Where m1, m2 is number of persons working
d1, d2 is number of days taken
h1, h2 is number of hours
w1, w2 is the units of work done
CALCULATION:
15 persons have taken a job of digging a pond in 20 days
Total work = 15 × 20 = 300 units
Work done by 15 men in 10 days = 15 × 10 = 150 units
Now,
5 men left the work
Work done by 10 men in 5 days = 10 × 5 = 50 units
Again 5 men left the work
Remaining work = 300 – (150 + 50) = 100 units
⇒ Remaining work will be done in 100/5 = 20 days
∴ Total number of days taken to complete the work = 10 + 5 + 20 = 35 days
A and B undertake to do a job for Rs. 6,000. A can do it in 10 days and B can do it in 12 days. With the assistance of C, they finish the work in 4 days. How much should C be paid for his work?
Answer (Detailed Solution Below)
Work and Wages Question 12 Detailed Solution
Download Solution PDFGiven:-
A can do a work in 10 days
B can do a work in 12 days
they undertake to do job for Rs. 6000
Concept used:-
Efficiancy concept related to work and time.
Total work = LCM(Time taken by all individual)
Calculation:-
Total work = LCM(10, 12)
Total work = 60 units
Rs. per unit = 6000/60 = 100 Rs. per unit
∴ A's per day work = 60/10 = 6 units
A's per day income = 6 × 100 = Rs. 600
B's per day work = 60/12 = 5 units
B's per day income = 5 × 100 = Rs. 500
Let C's per day work = x units
According to Question-
⇒ (6 × 4) + (5 × 4) + (x × 4) = 60
⇒ 24 + 20 + 4x = 60
⇒ 4x = 60 - 44
⇒ x = 16/4
⇒ x = 4 units
C's per day income = 4 × 100 = Rs. 400
∴ C should be paid for work = 400 × 4 = Rs.1600
A can do a piece of work in 20 days while B can do it in 30 days. They work together for 10 days and the rest of the work is done by C in 5 days. If they get Rs 560 for the whole work, how much money will A get?
Answer (Detailed Solution Below)
Work and Wages Question 13 Detailed Solution
Download Solution PDFGiven:
Time is taken by A to do the work = 20 days
Time is taken by B to do the work = 30 days
Total wage = Rs. 560
Formula used:
Time = Total work/Efficiency
Concept used:
Wage is divided the same as efficiency and inversely proportional to the time taken
Calculation:
Work done by A in 1 day is = 1/20
Work done by B in 1 day is = 1/30
Work done by A and B together in 1 day is = (1/20 + 1/30) = 1/12
Work is done by A and B together in 10 days is = 10/12
Remaining work = 1 – 10/12 = 2/12 = 1/6
C do 1/6 of the work in 5 days
Total work done by C alone in 5 × 6 is = 30 days
Wages ratio of A, B and C = 1/20 × 10 : 1/30 × 10 : 1/30 × 5 = 6 : 4 : 2
Money A will get = 6/12 × 560 = 280
∴ Share of money A will get is Rs 280
Shortcut Trick
Since A can do that piece of work in 20 days and has worked for 10 days
i.e. A has done half of total work.
So A will get half of the amount paid to all i.e. = 560/2 = Rs. 280
Confusion Points
You may think that 240 is the correct answer but it is not.
It is so because the time for which C has worked is 5 days whereas A and B have worked for 10 days.
Thus, Wages ratio of A, B and C = 1/20 × 10 : 1/30 × 10 : 1/30 × 5 = 6 : 4 : 2
If 15 boys earn Rs. 750 in 5 days, then how much money 25 boys will earn in 6 days?
Answer (Detailed Solution Below)
Work and Wages Question 14 Detailed Solution
Download Solution PDFGiven:-
15 boys for 5 days = at Rs 750
Calculation:-
Let 25 boys earn Rs. x in 6 days,
then according to question,
⇒ (15 × 5)/750 = (25 × 6)/x
⇒ x = 150 × 10
⇒ x = 1500
∴ 25 boys will earn Rs. 1500 in 6 days
Samir and Puneet can complete the same work in 10 days and 15 days respectively. The work was assigned for Rs.4500. After working together for 3 days Samir and Puneet involved Ashok. The work was completed in total 5 days. What amount (in Rs.) was paid to Ashok?
Answer (Detailed Solution Below)
Work and Wages Question 15 Detailed Solution
Download Solution PDFGiven:
Samir's 1 day's work = 1/10
Puneet's 1 day's work = 1/15
Calculation:
(Samir + Puneet)'s 1 day's work = 1/10 + 1/15 = 1/6
(Samir + Puneet)'s 3 days work = 3 × 1/6 = 1/2
Remaining work after 3 days = 1 - 1/2 = 1/2
Remaining work completed in 2 days.
(Samir + Puneet + Ashok)'s 1 day's work = 1/2 × 1/2 = 1/4
Ashok's 1 day's work = 1/4 - 1/6 = 1/12
Ratio of work done = 5/10 : 5/15 : 2/12
= 1/2 : 1/3 : 1/6
= 3 : 2 : 1
∴ Ashok's share = 1/6 × 4500 = Rs.750
Alternate Method Samir and Puneet can complete the same work in 10 days and 15 days respectively
Total work = LCM(10, 15) = 30 units
Efficiency of Samir = 30/10 = 3 units
Efficiency of Puneet = 30/15 = 2 units
According to the question,
Samir and Puneet worked for (3 + 2) = 5 days
Work done by Samir and Puneet in 5 days = 5 × 5 = 25 units
Remaining 5 units of work is done by Ashok in 2 days
Efficiency of Ashok = 5/2 = 2.5 units
Total amount = Rs. 4500
Amount given for 1 unit of work = 4500/30 = 150
Amount given to Ashok = 150 × 5 = Rs. 750