Train Crossing a Platform MCQ Quiz - Objective Question with Answer for Train Crossing a Platform - Download Free PDF
Last updated on Jun 5, 2025
Latest Train Crossing a Platform MCQ Objective Questions
Train Crossing a Platform Question 1:
Train P, which is ‘d’ meters long, takes the same time to pass a 300-meter-long platform as Train Q, which is (d + 200) meters long, takes to pass a 500-meter-long platform. If the ratio of their speeds (Train P to Train Q) is 5:9, then what is the value of d?
Answer (Detailed Solution Below)
Train Crossing a Platform Question 1 Detailed Solution
Calculation
Let speed of train P and Q be 5x m/sec. & 9x m/sec. respectively
ATQ,
[ (d+300) / 5x] = [(d+700) / 9x]
So, 9d + 2700 = 5d + 3500
So, 4d = 800
So, d = 200
Train Crossing a Platform Question 2:
Train A of length 80m while moving crosses a pole in 16 seconds. lf it is known that the lengths of train B and train A is in the ratio of 3:1, then how long would it take train B to cross a platform which is half the length of train A if the speed of train B is same as that of train A?
Answer (Detailed Solution Below)
Train Crossing a Platform Question 2 Detailed Solution
Calculations:
Speed of Train A = Distance / Time = 80 m / 16 s = 5 m/s.
Since the speed of Train B is the same as Train A, the speed of Train B = 5 m/s.
Length of Train B = 3 × Length of Train A
⇒ 3 × 80 = 240 m.
Length of the platform = (1/2) × Length of Train A
⇒ (1/2) × 80 = 40 m.
To cross the platform, Train B needs to cover its own length plus the length of the platform, i.e., 240 m + 40 m = 280 m.
Time taken by Train B to cross the platform = Distance / Speed
⇒ 280 m / 5 m/s = 56 seconds.
∴ It would take Train B 56 seconds to cross the platform.
Train Crossing a Platform Question 3:
Two trains of equal length are running on parallel lines in the same direction at speeds of 90 km/h and 51 km/h. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer (Detailed Solution Below)
Train Crossing a Platform Question 3 Detailed Solution
Given:
Speed of faster train = 90 km/h
Speed of slower train = 51 km/h
Time to cross = 36 seconds
Trains are of equal length and moving in the same direction
Formula used:
Relative Speed = (Speed₁ - Speed₂)
Distance = Relative Speed × Time
Length of each train = (Distance ÷ 2)
Calculation:
⇒ Relative Speed = 90 - 51 = 39 km/h
⇒ 39 km/h = 39 × (1000 ÷ 3600) = 10.83 m/s
⇒ Distance = 10.83 × 36 = 389.88 m
⇒ Length of each train = 389.88 ÷ 2 ≈ 194.94 m
∴ The length of each train is approximately 195 metres.
Train Crossing a Platform Question 4:
A goods train 350 m long passes through a tunnel of length 1250 m in 80 sec. What is the speed of the train?
Answer (Detailed Solution Below)
Train Crossing a Platform Question 4 Detailed Solution
Given:
Length of the goods train = 350 m.
Length of the tunnel = 1250 m.
Time taken to pass through the tunnel = 80 sec.
Formula Used:
Speed = Total Distance / Time
Calculation:
Total Distance = Length of the train + Length of the tunnel
Total Distance = 350 + 1250
Total Distance = 1600 m
Time = 80 sec
Speed = Total Distance / Time
Speed = 1600 / 80
Speed = 20 m/s
Convert m/s to km/hr:
Speed in km/hr = Speed in m/s × 18/5
Speed in km/hr = 20 × (18/5)
Speed in km/hr = 72 km/hr
The speed of the train is 72 km/hr.
Train Crossing a Platform Question 5:
Two trains are moving in opposite directions at speeds of 50 km/h and 110 km/h. The length of one train is 500 m. The time taken by them to cross each other is 12 seconds. The length (in m) of the other train, correct to 2 decimal places, is:
Answer (Detailed Solution Below)
Train Crossing a Platform Question 5 Detailed Solution
Given:
Speed of train 1 (S1) = 50 km/h
Speed of train 2 (S2) = 110 km/h
Length of train 1 (L1) = 500 m
Time to cross (t) = 12 seconds
Formula used:
Relative speed (opposite direction) = S1 + S2
Distance = Speed × Time
1 km/h = 5/18 m/s
When two trains cross each other, the total distance covered is the sum of their lengths.
Calculation:
Relative speed = 50 km/h + 110 km/h = 160 km/h
Convert relative speed to m/s:
⇒ 160 km/h = 160 × \(\frac{5}{18}\) m/s
⇒ Relative speed = \(\frac{800}{18}\) m/s = \(\frac{400}{9}\) m/s
Let the length of train 2 be L2.
Total distance covered = L1 + L2 = 500 + L2 meters
Using Distance = Speed × Time:
⇒ 500 + L2 = \(\frac{400}{9}\) × 12
⇒ 500 + L2 = \(\frac{400 \times 4}{3}\)
⇒ 500 + L2 = \(\frac{1600}{3}\)
⇒ 500 + L2 = 533.33
⇒ L2 = 533.33 - 500
⇒ L2 = 33.33
∴ The length of the other train is 33.33 m.
Top Train Crossing a Platform MCQ Objective Questions
Running at a speed of 60 km per hour, a train passed through a 1.5 km long tunnel in two minutes, What is the length of the train ?
Answer (Detailed Solution Below)
Train Crossing a Platform Question 6 Detailed Solution
Download Solution PDFGiven:
Speed is 60 km per hour,
Train passed through a 1.5 km long tunnel in two minutes
Formula used:
Distance = Speed × Time
Calculation:
Let the length of the train be L
According to the question,
Total distance = 1500 m + L
Speed = 60(5/18)
⇒ 50/3 m/sec
Time = 2 × 60 = 120 sec
⇒ 1500 + L = (50/3)× 120
⇒ L = 2000 - 1500
⇒ L = 500 m
∴ The length of the train is 500 m.
A train crossed a 110 m long platform in 13.5 seconds and a 205 m long platform in 18.25 seconds. What was the speed of the train?
Answer (Detailed Solution Below)
Train Crossing a Platform Question 7 Detailed Solution
Download Solution PDFLet the length of train be x m.
⇒ Speed of train = (length of platform + length of train)/time
According to question,
⇒ (110 + x)/ 13.5 = (205 + x)/18.25
⇒ (110 + x)/2.7 = (205 + x)/3.65
⇒ 401.5 + 3.65x = 553.5 + 2.7x
⇒ 0.95x = 152
⇒ x = 160
⇒ Speed of train = (110 + 160)/13.5 = 20 m/sec = 20 × (18/5) = 72 km/hrA 1200 m long train crosses a tree in 120 sec, how much time will it take to pass a platform 700 m long?
Answer (Detailed Solution Below)
Train Crossing a Platform Question 8 Detailed Solution
Download Solution PDFGiven:
Length of a train is 1200m
Train took 120 sec to cross a tree
Length of a platform is 700m
Formula USed:
Speed = Distance/Time
Calculation:
Speed = 1200/120 = 10 m/sec
Total distance = 1200 + 700 = 1900 m
Time = distance/speed = 1900/10 = 190 sec
∴ Time required to cross a platform is 190 sec.
A train passes a platform in 48 seconds and a passenger standing on the platform in 30 seconds. If the speed of the train is 72 km/hr, what is the length of the platform?
Answer (Detailed Solution Below)
Train Crossing a Platform Question 9 Detailed Solution
Download Solution PDFGiven:
Speed of the train = 72km/hr
The train passes the platform in 48 sec and the passenger in 30 sec
Concept used:
Speed = distance/time
While a train crossing a man it actually crossing it's own length.
Calculation:
Speed of the train is 72 km/hr = 72 × (5/18) = 20 m/sec
Length of train = speed × time
⇒ 20 × 30 = 600 m
Now, accordingly
\(20 = \;\frac{{x + 600}}{{48}}\)
⇒ \(20 × 48 = x + 600\)
⇒ x = 960 - 600
⇒ x = 360
∴ The length of the platform is 360 meter.
The time taken for the tail end of a train to cross a pole is 53 seconds. If the length of the train is 110 m and speed of the train is 36 km/hr, find the initial distance of the pole from the front end of the train.
Answer (Detailed Solution Below)
Train Crossing a Platform Question 10 Detailed Solution
Download Solution PDF⇒ Speed = Distance/time
⇒ Speed of train = 36 × (5/18) = 10m/s
⇒ Distance covered in 53 seconds = 10 × 53 = 530 m
⇒ Length of train = 110m
∴ The initial distance of the pole from the front end of the train = 530 – 110 = 420 m.A 250 meters long train crosses a bridge 750 meters long in 20 seconds and crosses a platform in 15 seconds. Find the length of the platform.
Answer (Detailed Solution Below)
Train Crossing a Platform Question 11 Detailed Solution
Download Solution PDFGiven:
A 250 meters long train crosses a bridge 750 meters long in 20 seconds
And crosses a platform in 15 seconds.
Formula Used:
Distance = Speed × Time
Calculation:
Let the speed of the train be S
And let the length of the platform be x
According to the question,
250 + 750 = S × 20
⇒ S = 1000/20
⇒ 50 m/sec
Now, Again according to the question
The train crosses the platform in 15 seconds
250 + x = 50 × 15
⇒ x = 750 - 250
⇒ x = 500 m
∴ The length of the platform is 500 m.
A train crosses a pole in 5 seconds and crosses the tunnel in 20 seconds. If the speed of the train 90 m/s, then find the length of the tunnel.
Answer (Detailed Solution Below)
Train Crossing a Platform Question 12 Detailed Solution
Download Solution PDFGiven:
Time to cross the pole = 5 sec
Time to crosses the tunnel = 20 sec
Formula used:
Speed = Distance/Time
Calculation:
Let the length of the tunnel be x m and the length of the train be y m
Time = Distance/Speed
⇒ 5 = (y/90)
⇒ y = 450 m
Time to crosses the tunnel = Distance/Speed
⇒ 20 = (y + x)/90
⇒ 20 × 90 = (450 + x)
⇒ x = 1800 - 450 = 1350
∴ The length of the tunnel is 1350 m.
A train crosses a pole in 12 sec, and a bridge of length 170 m in 36 sec. Then the speed of the train is:
Answer (Detailed Solution Below)
Train Crossing a Platform Question 13 Detailed Solution
Download Solution PDFFormula used:
Speed = Distance / Time
(1 m/s) × (18/5) = 1 km/hr
Shortcut Trick
If train cross its length in 12 seconds and 170 m bridge in (36 - 12 = 24) seconds.
Speed of train = [170/24] × [18/5] = 25.5 km/hr
Alternate Method
Let the length of the train be x m.
As we know,
Speed = Distance/time
Speed (v) = x/12
x = 12 v -----(1)
Again,
v = (x + 170)/36 -----(2)
From equation (1)
v = (12v + 170)/36
⇒ 36v = 12v + 170
⇒ 24v = 170
⇒ v = 170/24 m/s
⇒ v = (170/24) × (18/5) km/hr
∴ Speed = 25.5 km/hrA train crosses a 375 m long platform in 27 seconds. How long was the train if it was travelling at the speed of 70 km/h?
Answer (Detailed Solution Below)
Train Crossing a Platform Question 14 Detailed Solution
Download Solution PDFLet length of train be A meter.
⇒ 70 kmph = 70 × 5/18 = 175/9 m/sec
A train crosses a 375 m long platform in 27 seconds,
⇒ 175/9 = (375 + A) /27
⇒ 375 + A = 175 × 3
⇒ A = 150
∴ The length of the train = 150 mA train crosses a station platform in 36 seconds and crosses a man standing on the platform in 20 seconds. If the speed of the train is 54 km/h, what is the length of the platform?
Answer (Detailed Solution Below)
Train Crossing a Platform Question 15 Detailed Solution
Download Solution PDFGiven:
A train crosses a station platform in 36 seconds
And crosses a man standing on the platform in 20 seconds
The speed of the train is 54 km/h
Formula Used:
Speed = Distance/Time
Calculation:
Let the length of the train be x m and the length of the platform be y m
According to the question
54 × (5/18) = x/20
⇒ 15 × 20 = x
⇒ x = 300 m
Again, According to the question
⇒ 54 × (5/18) = (300 + y) /36
⇒ 15 × 36 = 300 + x
⇒ y = 540 – 300
⇒ y = 240
∴ The length of the platform is 240.
Shortcut Trick As given train cross its length in 20 seconds.
So the train cross the platform in = 36 – 20 = 16 seconds
The distance covered by train in 16 seconds = 54 × (5/18) × 16 = 240