Which of the following conversion formula is correct for temperature units 

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ISRO IPRC Technical Assistant Mechanical 10 Dec 2016 Official Paper
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  1. \(\frac C{100}= \frac {F-32}{180}=\frac {R-492}{180}\)
  2. \(\frac C{100}= \frac {F-32}{180}=\frac {R-460}{180}\)
  3. \(\frac C{100}= \frac {F-32}{180}=\frac {R}{180}\)
  4. None of the above

Answer (Detailed Solution Below)

Option 1 : \(\frac C{100}= \frac {F-32}{180}=\frac {R-492}{180}\)
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Detailed Solution

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Explanation:

Celsius scale 

  • In this scale, LFP (ice point) is taken 0° and UFP (steam point) is taken 100°.
  • The temperature measured on this scale all in degree Celsius (° C).

Fahrenheit scale 

  • This scale of temperature has LFP as 32° F and UFP as 212° F .
  • The change in temperature of 1° F corresponds to a change of less than 1° on the Celsius scale.

Kelvin scale 

  • The Kelvin temperature scale is also known as the thermodynamic scale. The triple point of water is also selected to be the zero of the scale of temperature.
  • The temperatures measured on this scale are in Kelvin (K).

Rankine scale

  • This scale of temperature has LPF as 492° R and UFP as 672° R.
  • Interval of this scale is according to Fahrenheit.
  • The temperature measured on this scale are in Rankine (R)

 

All these temperatures are related to each other by the following relationship

\(\frac C{100}= \frac {F-32}{180}=\frac {R-492}{180}= \frac {K -273}{100}\)

Additional Information

Relationship between the Celsius and Fahrenheit scale is –

\(\frac{F-32}{9}=\frac{C}{5}\)

\(\Rightarrow C=\frac{5}{9}\left( F-32 \right)\)

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