Question
Download Solution PDFWhen a number is divided by 15, 20 or 35, each time the remainder is 8. Then the smallest number is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Given numbers
15, 20 and 35
The smallest number will be the LCM (Least Common Multiple) of these three numbers.
Let us find the prime factors for each number
15 = 3 × 5
20 = 2 × 2 × 5
35 = 5 × 7
The LCM of the three numbers is given by
LCM = 2 × 2 × 5 × 3 × 7 = 420
420 is exactly divisible by 15, 20, and 35.
Since we have a remainder of 8 in each case, the smallest number in each case will be given by
= 420 + 8 = 428.
Last updated on Jan 29, 2025
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